Question

What is the equation of the line that is parallel to y = negative two-thirds x + 4 and that passes through (–2,–2)?

Answer 1

Answer:

The answer is

y = -2/3x - 10/3

Step-by-step explanation:

Equation of a line is y = mx + c

where m is the slope

c is the y intercept

y = -2/3x + 4

Comparing with the above formula

m / slope = - 2/3

Since the lines are parallel their slope are also the same

Thus

Slope of the parallel line = -2/3

Equation of the line using point ( - 2 , - 2) is

$y + 2 = - \frac{2}{3} (x + 2)$

$y + 2 = - \frac{2}{3} x - \frac{4}{3}$

$y = - \frac{2 }{3} x - \frac{4}{3} - 2$

We have the final answer as

$y = - \frac{2}{3} x - \frac{10}{3}$

Hope this helps you