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Readme [11.4K]
3 years ago
7

Help help math math math

Mathematics
2 answers:
Alika [10]3 years ago
5 0
The correct answer is Y= -21
Ronch [10]3 years ago
3 0

y=-6x+12\\\\\text{When}~  x = -1\\\\y=-6(-1)+12 = 6+12 = 18

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HELP :(
morpeh [17]

Answer:

6670/2=3335 answer:3335

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
If f(x)=3x^2-2x+5, find f(-2)<br><br> a) -27<br> b) -11<br> c) -3<br> d) 21
Talja [164]

Answer:

D

Step-by-step explanation:

f(x) = 3x^2 - 2x + 5

f(-2) means that wherever you see an x on the right, you put in the value of -2 for the x.

f(-2) = 3(-2)^2 - 2(-2) + 5

f(-2) = 3(4) + 4 + 5

f(-2) = 12 + 9

f(-2) = 21

The answer is D

3 0
3 years ago
Average rate of change please helpp
Vera_Pavlovna [14]

The average rate of change over the interval [-9, -3] is

\dfrac{f(-3) - f(-9)}{-3 - (-9)}

That is, it's the ratio between the change in the function value over the length of the interval. Judging by the plot, we have <em>f</em> (-9) = 6 and <em>f</em> (-3) = -3. So the average rate of change is

\dfrac{f(-3) - f(-9)}{-3 - (-9)} = \dfrac{-3 - 6}{-3 + 9} = -\dfrac96 = \boxed{-\dfrac32}

7 0
3 years ago
from the edge of a 486-foot cliff, peyton shot an arrow over the ocean with an initial upward velocity of 90-feet per second
anygoal [31]

Answer:

9 seconds

Step-by-step explanation:

The complete question is

The altitude of an object, d, can be modeled using the equation below:

d=-16t^2 +vt+h

from the edge of a 486 foot cliff, Peyton shot an arrow over the ocean with an initial upward velocity of 90 feet per second. In how many seconds will the arrow reach the water below?

Let

d ----> the altitude of an object in feet

t ---> the time in seconds

v ---> initial velocity in ft per second

h ---> initial height of an object in feet

we have

d=-16t^2 +vt+h

we  know that

When the arrow reach the water the value of d is equal to zero

we have

v=90\ ft/sec

h=486\ ft

d=0\ ft

substitute the values and solve for t

0=-16t^2 +(90)t+486

-16t^2+90t+486=0

Multiply by -1 both sides

16t^2-90t-486=0

The formula to solve a quadratic equation of the form ax^{2} +bx+c=0 is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

a=16\\b=-90\\c=-486

substitute in the formula

t=\frac{90(+/-)\sqrt{-90^{2}-4(16)(-486)}}{2(16)}

t=\frac{90(+/-)\sqrt{39,204}}{32}

t=\frac{90(+/-)198}{32}

t_1=\frac{90(+)198}{32}=9\ sec

t_2=\frac{90(-)198}{32}=-3.375\ sec

the solution is t=9 sec

see the attached figure to better understand the problem

4 0
3 years ago
Its Distributive Property please help lol..
olasank [31]

Answer:

d= -4

Step-by-step explanation:

First you multiply the 3 by 6. You don't multiply the Coefficient with the variable.

(6x3)+5d = -2

Then you'll get: 18 + 5d = -2

At this point you just subtract from both sides

18 + 5d= -2

-18           -18

This becomes 5d = -20

\frac{5d}{5} =\frac{-20}{5}

-20/5 equals -4.

4 0
3 years ago
Read 2 more answers
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