5*5%5*5-*-2... I'm so messed up I'm stuck it doesn't even make sense, this question
Problem 1) xy means "x times y". The multiplication symbol is left out because its implied. You can write x*y if you wish. Or we can say "product of two numbers" since a product in math terms is the result of multiplication.
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Problem 2) x/y means "x divided by y" which is a fraction
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Problem 3)
Writing "x-y" is the same as saying "x minus y"
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Problem 4)
x+y is "x plus y", or we can say "the sum of x and y". The "sum" is "result of adding two or more values"
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Problem 5)
y-x is "y minus x" or we can say "x subtracted from y"
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Problem 6)
y division symbol x is essentially the flip of problem 2. We'd say "y divided by x"
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Problem 7)
x+y = 6 is "the sum of two numbers is 6". See problem 4 above.
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Problem 8)
xy = 6 is "the product of two numbers is 6". This is an extension of problem 1.
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Problem 9)
6x = y is "six times a number equals y" when translated out
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Problem 10)
y = x-6 would translate to "six less than a number is y"
where the "a number" portion is represented by x
Answer: M = ⁹/₅S
Step-by-step explanation:
M ∞ S -------------------------------- 1
M = KS ------------------------------ 2
K is a constant and need to be calculated
substitute for M and S in 2 to find K
900 = K500
K = ⁹⁰⁰/₅₀₀
= ⁹/₅
Therefore , the equation that connect / relates M to S will be
M = KS
M = ⁹/₅S
Answer:
Step-by-step explanation:
Area of a circle is ...
A = πr² . . . r is the radius
Area of a sphere is ...
A = 4πr²
Lateral area of a cylinder is ...
A = πdh = 2πrh . . . h is the height
Volume of a cylinder is ...
V = πr²h
Volume of a sphere is ...
V = (4/3)πr³
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The area of the composite figure is the sum of the areas ...
total area = base circle area + cylinder lateral area + 1/2 sphere area
= πr² + 2πrh + (1/2)4πr² = (πr)(r +2h +2r)
= πr(3r +2h)
For the given dimensions, r=3 in, h = 13 in, this is ...
total area = π(3 in)((3·3 +2·13) in) = 105π in²
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The volume of the composite figure is the sum of the volumes ...
total volume = cylinder volume + 1/2 sphere volume
= πr²h + (1/2)(4/3)πr³ = πr²(h + 2/3r)
= π(3 in)²((13 +2/3·3) in) = 135π in³