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3 years ago

How do i solve this answer ugh please help

Mathematics

1 answer:

babunello [35]3 years ago

6 0

Separate the quadratic functions into two individual function in x which multiply together to equal the original quadratic.
Eg: x^2-3x-10=0 can be written as (x+2)(x-5)=0
The two solutions for x can then be determined by making each bracket equal to zero.
x+2=0 so x=-2x-5=0 so x=5

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The slope and y-intercept of a line that goes though (0,4) and (-5,5)

Sphinxa [80]

Answer:

slope= -1/5 y intercept 3

Step-by-step explanation:

(0,4) and (-5,5) can be rewriten as 5-4/-5-0, which equals -1/5. Then, you plug the numbers into the equation y= mx+b to get -4=-1/5(5)+b. That gets 3.

5 0

3 years ago

There's a pair of points (3,5), (x,15) and a slope of 2 how do I find x

sergeinik [125]

You have the slope and you have two points, so you can use the slope equation to find x.

$b=\frac{(y_2-y_1)}{(x_2-x_1)} \\2=\frac{(15-5)}{(x-3)} \\2(x-3)=(15-5)\\2x-6=10\\2x=16\\x=8$

So your answer is x = 8.

8 0

3 years ago

Read 2 more answers

Can someone please help me

frozen [14]

No, the two rectangles are not similar. Similar rectangles will have the same ratio of shortest to longest side lengths.
3 : 4 ≠ 5 : 6

3 0

3 years ago

If one card is drawn from a standard deck of 52 playing cards what is the probability of it is not a heart

dmitriy555 [2]

I forgot how many of each card there are and if you're counting the joker.
But just find the number of heart cards, and minus that from 52.
The answer divided by 52 is the probability that it's not a heart.

6 0

4 years ago

The same survey database cited in exercise 4.3.1 (A-5) shows that 32 percent of U.S. adults indicated that they have been tested

yawa3891 [41]

Answer:

a. P(X = 3) = 0.145736

b. P(5≤X≤9) = 0.5462

c. P(5<X<10) = 0.3332

d. P(X≥6) = 0.3393

e. P(X<5) = 0.4477

f. Mean = 4.8, Variance = 3.264

Step-by-step explanation:

Given - The same survey database cited in exercise 4.3.1 (A-5) shows

that 32 percent of U.S. adults indicated that they have been

tested for HIV at some point in their life. Consider a simple

random sample of 15 adults selected at a time. Let X be the

number of adults who have been tested for HIV in the sample.

To find - For the following, find the numerical answer and describe

the answer in words:

a. Three

b. Between five and nine, inclusive

c. More than five, but less than 10

d. Six or more

e. Less than five

f. Find the mean and the variance of the number of people

tested for HIV in samples of size 15.

Proof -

Given that , n = 15, p = 32% = 0.32

Now,

P(X = 3) = binomial distribution (3, 15, 0.32, 0)

= $\left(\begin{array}{ccc}15\\3\end{array}\right)(0.32)^{3}(1-0.32)^{15 - 3}$

= 455(0.032768)(0.009774)

= 0.145736

⇒P(X = 3) = 0.145736

P(5≤X≤9) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9)

= $\left(\begin{array}{ccc}15\\5\end{array}\right)(0.32)^{5}(1-0.32)^{15 - 5}$ + $\left(\begin{array}{ccc}15\\6\end{array}\right)(0.32)^{6}(1-0.32)^{15 - 6}$ + $\left(\begin{array}{ccc}15\\7\end{array}\right)(0.32)^{7}(1-0.32)^{15 - 7}$ + $\left(\begin{array}{ccc}15\\8\end{array}\right)(0.32)^{8}(1-0.32)^{15 - 8}$ + $\left(\begin{array}{ccc}15\\9\end{array}\right)(0.32)^{9}(1-0.32)^{15 - 9}$

= 0.213 + 0.1671 + 0.1011 + 0.0476 + 0.0174

= 0.5462

⇒P(5≤X≤9) = 0.5462

P(5<X<10) = + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9)

= $\left(\begin{array}{ccc}15\\6\end{array}\right)(0.32)^{6}(1-0.32)^{15 - 6}$ + $\left(\begin{array}{ccc}15\\7\end{array}\right)(0.32)^{7}(1-0.32)^{15 - 7}$ + $\left(\begin{array}{ccc}15\\8\end{array}\right)(0.32)^{8}(1-0.32)^{15 - 8}$ + $\left(\begin{array}{ccc}15\\9\end{array}\right)(0.32)^{9}(1-0.32)^{15 - 9}$

= 0.1671 + 0.1011 + 0.0476 + 0.0174

= 0.3332

⇒P(5<X<10) = 0.3332

P(X≥6) = 1 - P(X < 6)

= 1 - P(X ≤ 5)

= 1 - binomial(5, 15, 0.32, 1)

= 1 - 0.6607

= 0.3393

⇒P(X≥6) = 0.3393

P(X<5) = P(X≤4)

= binomial (4, 15, 0.32, 1)

= 0.4477

⇒P(X<5) = 0.4477

Mean = np

= 15(0.32)

= 4.8

⇒Mean = 4.8

Variance = np(1-p)

= 15(0.32)(1 - 0.32)

= 4.8(0.68)

= 3.264

⇒Variance = 3.264

3 0

3 years ago