Question

If f(x) is an even function and (6, 8) is one the points on the graph of f(x), which reason explains why (–6, 8) must also be a point on the graph?
Since the function is even, the outputs of a negative x-value and a positive x-value are the same.

Since the function is even, the outputs of a negative y-value and a positive y-value are the same.

The graph has rotational symmetry, so the point will be reflected across the y-axis.

The graph has rotational symmetry, so the point will be rotated 90 degrees about the origin.

PLEASE HELP IM IN THE MIDDLE OF A TEST

Answer 1

If $f(x)$ is an even function, then $f(x)=f(-x)$. In this case, $f(6)=8=f(-6)$.

This is because an even function is symmetric about the $y-axis$. Hence the outputs of a negative x-value and a positive x-value are the same.

The correct option is the first option.

Since the graph is even, the outputs of a negative x-value and a positive x-value are the same.