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yKpoI14uk [10]
3 years ago
13

If f(x) is an even function and (6, 8) is one the points on the graph of f(x), which reason explains why (–6, 8) must also be a

point on the graph?
Since the function is even, the outputs of a negative x-value and a positive x-value are the same.

Since the function is even, the outputs of a negative y-value and a positive y-value are the same.

The graph has rotational symmetry, so the point will be reflected across the y-axis.

The graph has rotational symmetry, so the point will be rotated 90 degrees about the origin.

PLEASE HELP IM IN THE MIDDLE OF A TEST
Mathematics
heidi
2 years ago
I'm taking that test rn lol
1 answer:
Vikki [24]3 years ago
4 0

If f(x) is an even function, then f(x)=f(-x). In this case, f(6)=8=f(-6).


This is because an even function is symmetric about the y-axis. Hence the outputs of a negative x-value and a positive x-value are the same.


The correct option is the first option.

Since the graph is even, the outputs of a negative x-value and a positive x-value are the same.


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