A car is traveling at a speed of 75 km/h. Compute the speed of the car in m/s.

Algebra help needed

lesantik [10]

Answer:

The ball will reach the ground when h=0.

Set the equation equal to 0.

$0=-8(2 t-4)(t+1)$

$t=-1,2$

Step-by-step explanation:

The height of a golf ball after it has been hit from the top of a hill can be modeled by the equation

$h=-8(2 t-4)(t+1)$ ,

where h is the height in feet and t is time in seconds.

When ball will reach the ground the distance between ball and ground is 0. So, the ball will reach the ground when h=0.

To find the time it takes for the ball to reach the ground, set the equation equal to 0 and use the Zero Product Property to solve for $t$.

$h=-8(2 t-4)(t+1)$

$\Rightarrow 0=-8(2 t-4)(t+1)$

Solve the equation using the Zero Product Property.

$2t-4=0\Rightarrow t=\dfrac{4}{2}=2$

$t+1=0\Rightarrow t=-1$

So, $t=-1,2$

7 0

3 years ago

Given rectangle ABCD with vertices A(1, 4), B(3, 6), C(6, 3), and D(4, 1), what is the

Hitman42 [59]

Answer:

10√2

Step-by-step explanation:

A(1, 4), B(3, 6), C(6, 3), D(4, 1)

The distance formula tells you the distance d between two points (x1, y1) and (x2, y2) is given by ...

d = √((x2-x1)² +(y2-y1)²

Then the side lengths are ...

AB = √(2² +2²) = √8 = 2√2

BC = √(3² +(-3)²) = √18 = 3√2

The perimeter is twice the sum of these sides, so is ...

P = 2(2√2 +3√2) = 10√2 . . . the perimeter of the rectangle

6 0

3 years ago

a gift shop sells 160 wind chimes per month at $150 each. the owners estimate that for each $15 increase in price, they will sel

adell [148]

Answer:

The price per wind chime that will maximize revenue = $ 315

Step-by-step explanation:

Given - A gift shop sells 160 wind chimes per month at $150 each. the owners estimate that for each $15 increase in price, they will sell 5 fewer wind chimes per month.

To find - Find the price per wind chime that will maximize revenue.

Proof -

Given that,

Total Wind chimes selling = 160

Price of each Wind chime = $150

Now,

Given that, for each $15 increase in price, they will sell 5 fewer wind chimes per month.

So,

Let the price = 150 + 15x

So,

Number of wind Chimes sold per month = 160 - 5x

So,

Total Revenue, R = (150 + 15x)(160 - 5x)

= 24000 - 750x + 2400x - 75x²

= 24000 + 1650x - 75x²

⇒R(x) = 24000 + 1650x - 75x²

Differentiate R with respect to x , we get

R'(x) = 1650 - 150x

Now,

For Maximize Revenue, Put R'(x) = 0

⇒1650 - 150x = 0

⇒150x = 1650

⇒x = 1650/150

⇒x = 11

∴ we get

Price per Wind chime = $ 150 + 15(11)

= $ 150 + 165

= $ 315

So,

The price per wind chime that will maximize revenue = $ 315

3 0

3 years ago

Plz help ill give u brainlist

Sindrei [870]

He needs 25 cm^3 of sand

good luck

6 0

3 years ago

Solve by factoring. x² - 121 = 0

densk [106]

The first one is 11 and -11 because when you square them they both get 121
The second one is -7 and -1

4 0

3 years ago