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Mrac [35]
2 years ago
11

Solve for X: Correctly answer the question

Mathematics
1 answer:
Klio2033 [76]2 years ago
3 0

Answer:

x=16

Step-by-step explanation:

(whole secant) x (external part) = (tangent)^2

(8+24) * 8 = x^2

32*8 = x^2

256  =x^2

Take the square root of each side

sqrt(256) = sqrt(x^2)

16 = x

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Which expressions are equivalent to 2 (three-fourths x 7) minus 3 (one-half x minus 5)? Check all that apply. -1 29 2 (three-fou
Otrada [13]

The expression is equivalent to \rm2( \dfrac{3}{4}x) + 2(7) -3(\dfrac{1}{2}x) + (-3) (-5)\\.

<h2 /><h2>Given that</h2>

Expression; \rm 2(\dfrac{3}{4}x+7) -3(\dfrac{1}{2}x-5)

<h3>We have to determine</h3>

Which expressions are equivalent to the given expression.

<h3>According to the question</h3>

Expression; \rm 2(\dfrac{3}{4}x+7) -3(\dfrac{1}{2}x-5)

To solve the given expression follow all the steps given below.

By applying the distributive property of multiplication;

\rm a(b+c) = ab+ac

Then,

The equivalent expression is,

\rm 2(\dfrac{3}{4}x+7) -3(\dfrac{1}{2}x-5)\\&#10;\\&#10;\rm (2 \times \dfrac{3}{4}x) + 2(7) -3(\dfrac{1}{2}x) + (-3) (-5)\\&#10;\\&#10;2( \dfrac{3}{4}x) + 2(7) -3(\dfrac{1}{2}x) + (-3) (-5)\\

Hence, the expression is equivalent to \rm2( \dfrac{3}{4}x) + 2(7) -3(\dfrac{1}{2}x) + (-3) (-5)\\.

To know more about Equation click the link given below.

brainly.com/question/13174611

5 0
2 years ago
I have to round an answer to the nearest tenth. My original answer is 15.98. Do I go to 16, or 15.9? Please answer soon.
puteri [66]

Answer:

16

Step-by-step explanation: becuase you have to round it think to urself is it closer to 15.9 or 16

3 0
3 years ago
A village experienced 2% population growth, compounded continuously, each year for 10 years. At the end of the 10 years, the pop
pantera1 [17]

Answer:

The initial population at the beginning of the 10 years was 129.

Step-by-step explanation:

The population of the village may be modeled by the following function.

P(t) = P_{0}e^{rt}

In which P is the population after t hours, P_{0} is the initial population and r is the growth rate, in decimal.

In this problem, we have that:

P(10) = 158, r = 0.02.

So

158 = P_{0}e^{0.02*10}

P_{0} = 158*e^{-0.2}

P_{0} = 129

The initial population at the beginning of the 10 years was 129.

6 0
3 years ago
Read 2 more answers
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