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IgorC [24]
3 years ago
12

Can some one help on 30? thx

Mathematics
2 answers:
Kisachek [45]3 years ago
8 0
14 days will pass before doin it again
MariettaO [177]3 years ago
5 0
The lowest common multiple of 2 and 7 is 14, so 14 days will pass before he does both chores again. 
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whenever Sabrina visits the gym she lifts weights for 8 minutes and runs on the treadmill for 35 minutes. write two equivalent e
Darya [45]
Your answer will be 8+35×5=215 because she works out 43 minutes total a day (8+35=43) and then you have to do that for 5 more more day so you can do 43 × 5 or 43+43+43+43+43 your answer will come out the same
5 0
3 years ago
What's the answer to 4n - 9 = -9
aksik [14]
Hello!

You solve this algebraically

4n - 9 = -9

Add 9 to both sides

4n = 0

Divide both sides by 4

n = 0

The answer is 0

Hope this helps!
8 0
3 years ago
Read 2 more answers
A job can be done by 30 men in 15 days. How long would it take 10 men to do the same job?​
Vladimir79 [104]

Answer:

5 days

Step-by-step explanation:

This questions involves ratios, the job with 30 men can be done in 15 days, so the ratio from amount of men to amount of days the job will take to complete, it is 30:15. If we had 10 men instead of 30, 10 is one-third of 30, so you have to divide by 3 on each side of the ratio to get your answer.

If we do that we get the ratio 10:5.

Meaning that the 5 is the amount of days needed to be taken in order the complete the job.

Hope this helps!

3 0
3 years ago
Which fact is related to 12 : 3 = 4
goblinko [34]

Answer:

3x4 = 12 is the most related fact to 12:3 = 4

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Find a function where f(0)=2 and f(1)=2
xenn [34]

Answer:

Do you want to be extremely boring?

Since the value is 2 at both 0 and 1, why not make it so the value is 2 everywhere else?

f(x) = 2 is a valid solution.

Want something more fun? Why not a parabola? f(x)= ax^2+bx+c.

At this point you have three parameters to play with, and from the fact that f(0)=2 we can already fix one of them, in particular c=2. At this point I would recommend picking an easy value for one of the two, let's say a= 1 (or even a=-1, it will just flip everything upside down) and find out b accordingly:f(1)=2 \rightarrow 1^2+b+2=2 \rightarrow b=-1

Our function becomes

f(x) = x^2-x+2

Notice that it works even by switching sign in the first two terms: f(x) = -x^2+x+2

Want something even more creative? Try playing with a cosine tweaking it's amplitude and frequency so that it's period goes to 1 and it's amplitude gets to 2: f(x) = A cos (kx)

Since cosine is bound between -1 and 1, in order to reach the maximum at 2 we need A= 2, and at that point the first condition is guaranteed; using the second to find k we get 2= 2 cos (k1) = cos k = 1 \rightarrow k = 2\pi

f(x) = 2cos(2\pi x)

Or how about a sine wave that oscillates around 2? with a similar reasoning you get

f(x)= 2+sin(2\pi x)

Sky is the limit.

8 0
2 years ago
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