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Neporo4naja [7]
3 years ago
7

Answer ASAP and whoever get it right can have brainliest!

Mathematics
2 answers:
MA_775_DIABLO [31]3 years ago
6 0

Step-by-step explanation:

= 1 \frac{1}{5}  \div  \frac{1}{10}  \\

=  \frac{1 \times 5 + 1}{5}  \div  \frac{1}{10}  \\

= \frac{6}{5}  \times  \frac{10}{1} \\

= \frac{60}{5}  \\

=\frac{60 \div 5}{5 \div 5}  \\

=\frac{12}{1}  \\

lapo4ka [179]3 years ago
4 0

Answer:

1 1/5 divided by 1/10 is 12

Step-by-step explanation:

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(8)<br>-5- h=-19 im having a hard time solving this​
11Alexandr11 [23.1K]

Answer:

h=(-22) i believe.

Step-by-step explanation:

(8)-5=3

3-h(or -22)=-19

4 0
4 years ago
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If you reflect ABCD across x-axis, what will be the coordinates of A’ and C’
disa [49]

Answer:

A (1, -5), B (2, -5)

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4 years ago
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Which expression below is an equivalent expression to: (13n^4+12n^3-3+8n^2)+(-11n^2-n^3)
Lubov Fominskaja [6]

Answer:

-13n^4 + 11n^3 - 3n^2 - 3

Step-by-step explanation:

*I think you mistyped the question. I belive the 13n^4 is supposed to be negative*


1.First, we need to add common values (all the n^4s together, all the n^3s, etc.) from the two sets.

-13n^4

12n^3 + -n^3

8n^2 + -11n^2

-3

2. Now lets simplify

-13n^4

11n^3

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3. Laststly, we put them all into one expression!

-13n^4 + 11n^3 - 3n^2 - 3

5 0
4 years ago
ASAP I NEED THIS NOW
UkoKoshka [18]

Answer:c

Step-by-step explanation:

3 0
3 years ago
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A jewelry box has a length that is 2 inches longer than the width and a height that is 1 inch smaller than the width. the volume
maxonik [38]
Given that a <span>jewelry box has a length that is 2 inches longer than the width and a height that is 1 inch smaller than the width.

Let the width of the box be w, then the length of the box is given by l = w + 2 and the height of the box is given by h = w - 1.

The volume of a box is given by

V=l\times w\times h \\  \\ =w(w+2)(w-1) \\  \\ =w(w^2+w-2)=w^3+w^2-2w

Given that the volume of the box is 140 cubic inches. Thus

w^3+w^2-2w=140

Thus, the width of the jewelry box is obtained as follows

w^3+w^2-2w=140 \\  \\ \Rightarrow w^3+w^2-2w-140=0 \\  \\ \Rightarrow(w-5)(w^2+6w+28)=0 \\  \\ \Rightarrow w=5

Therefore, the width of the jewelry box is 5 inches.

*Note that w^2+6w+28=0 gives complex roots, so we did not use it.
</span>
7 0
3 years ago
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