0 lightbulbs would be expected to burn out in 1800 hours
Answer:
0.44
Step-by-step explanation:
Given the estimated logistic regression model on risk of having squamous cell carcinoma
-4.84 + 4.6*(SMOKER)
SMOKER = 0 (non-smoker) ; 1 (SMOKER)
What is the predicted probability of a smoker having squamous cell carcinoma?
exp(-4.84 + 4.6*(SMOKER)) / 1 + exp(-4.84 + 4.6*(SMOKER))
SMOKER = 1
exp(-4.84 + 4.6) / 1 + exp(-4.84 + 4.6)
exp^(-0.24) / (1 + exp^(-0.24))
0.7866278 / 1.7866278
= 0.4402863
= 0.44
A. Yes, the value of this function is 8 when x is 15.
B. False. I noted right away that the ordered pair (0,5) is not included, and some of the ordered pairs included do not represent the given function.
C. Yes, f(5) = 6. See (A) above.
D. False. The range of this function is the set of integers between 5 and 13 inclusive.
Answer:
The mean of the data is 26.
Step-by-step explanation:
Consider the provided data:
30, 29, 28, 30, 24, 12, 26, 33, 25, 23
Mean can be calculated as:
The average of all the data in a set.
Therefore,
Thus, the mean of the data is 26.
Answer:
ĉu vi scias ion, ni supozeble ne scias tion, jes
