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liubo4ka [24]
2 years ago
5

Which statement is most likely to be true? the ages of the mackerels are the most dispersed from the team’s mean. the ages of th

e stars are the most dispersed from the team’s mean. the ages of the dolphins are the most dispersed from the team’s mean. the ages of the giants are the most dispersed from the team’s mean.
Mathematics
1 answer:
MakcuM [25]2 years ago
6 0

The ages of the Stars are the most dispersed from the team’s mean

<h3> Which statement is right?</h3>

Standard deviation is one way to measure the average of the data by determining the spread of the data. It actually explains how much the observation points are further away from the mean of the data.

Higher the standard deviation, higher the spread of the data and higher is the uncertainty. This means that the team with the highest standard deviation will have the most dispersion.

In this case, the standard deviation of 4.1 is the largest number, therefore, the statement "The ages of the Stars are the most dispersed from the team’s mean." is true

To know more about standard deviation follow

brainly.com/question/475676

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A sample of salary offers (in thousands of dollars) given to management majors is: 48, 51, 46, 52, 47, 48, 47, 50, 51, and 59. U
balu736 [363]

Answer:

Step-by-step explanation:

number of samples, n = 10

Mean = (48 + 51 + 46 + 52 + 47 + 48 + 47 + 50 + 51 + 59)/10 = 49.9

Standard deviation = √(summation(x - mean)/n

Summation(x - mean) = (48 - 49.9)^2 + (51 - 49.9)^2 + (46 - 49.9)^2+ (52 - 49.9)^2 + (47 - 49.9)^2 + (48 - 49.9)^2 + (47 - 49.9)^2 + (50 - 49.9)^2 + (51 - 49.9)^2 + (59- 49.9)^2 = 128.9

Standard deviation = √128.9/10 = 3.59

Confidence interval is written in the form,

(Sample mean - margin of error, sample mean + margin of error)

The sample mean, x is the point estimate for the population mean.

Margin of error = z × s/√n

Where

s = sample standard deviation

From the information given, the population standard deviation is unknown and the sample size is small, hence, we would use the t distribution to find the z score

In order to use the t distribution, we would determine the degree of freedom, df for the sample.

df = n - 1 = 10 - 1 = 9

Since confidence level = 95% = 0.95, α = 1 - CL = 1 – 0.95 = 0.05

α/2 = 0.05/2 = 0.025

the area to the right of z0.025 is 0.025 and the area to the left of z0.025 is 1 - 0.025 = 0.975

Looking at the t distribution table,

z = 2.262

Margin of error = 2.262 × 3.59/√10

= 2.57

the lower limit of this confidence interval is

49.9 - 2.57 = 47.33

the lower limit of this confidence interval is

49.9 + 2.57 = 52.47

So it is false

6 0
2 years ago
Christine's age is two times sydney's age. the sum of their ages is 54. what is sydneys age?
Naddika [18.5K]
Let Sydney's age be x
Christine's age is 2x

Sum of their age is 54
x + 2x = 54
3x = 54
x = 18

Sydney is 18 years old.
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mestny [16]

Answer:

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Step-by-step explanation:

155.79-16.95=138.84

138.84/0.89=156

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