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liubo4ka [24]
2 years ago
5

Which statement is most likely to be true? the ages of the mackerels are the most dispersed from the team’s mean. the ages of th

e stars are the most dispersed from the team’s mean. the ages of the dolphins are the most dispersed from the team’s mean. the ages of the giants are the most dispersed from the team’s mean.
Mathematics
1 answer:
MakcuM [25]2 years ago
6 0

The ages of the Stars are the most dispersed from the team’s mean

<h3> Which statement is right?</h3>

Standard deviation is one way to measure the average of the data by determining the spread of the data. It actually explains how much the observation points are further away from the mean of the data.

Higher the standard deviation, higher the spread of the data and higher is the uncertainty. This means that the team with the highest standard deviation will have the most dispersion.

In this case, the standard deviation of 4.1 is the largest number, therefore, the statement "The ages of the Stars are the most dispersed from the team’s mean." is true

To know more about standard deviation follow

brainly.com/question/475676

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[4 -4 0 0]+[4 -2 2 -4]
jok3333 [9.3K]

Answer:

[8 -6 2 -4].

Step-by-step explanation:

[4 -4 0 0]+[4 -2 2 -4]

= [4+4 -4+-2 0+2 0+-4]

= [8 -6 2 -4]

6 0
3 years ago
Choose the best coordinate system to find the volume of the portion of the solid sphere rho &lt;_4 that lies between the cones φ
MrRissso [65]

Answer:

So,  the volume is:

\boxed{V=\frac{128\sqrt{2}\pi}{3}}

Step-by-step explanation:

We get the limits of integration:

R=\left\lbrace(\rho, \varphi, \theta):\, 0\leq \rho \leq  4,\, \frac{\pi}{4}\leq \varphi\leq \frac{3\pi}{4},\, 0\leq \theta \leq 2\pi\right\rbrace

We use the spherical coordinates and  we calculate a triple integral:

V=\int_0^{2\pi}\int_{\frac{\pi}{4}}^{\frac{3\pi}{4}}\int_0^4  \rho^2 \sin \varphi \, d\rho\, d\varphi\, d\theta\\\\V=\int_0^{2\pi}\int_{\frac{\pi}{4}}^{\frac{3\pi}{4}} \sin \varphi \left[\frac{\rho^3}{3}\right]_0^4\, d\varphi\, d\theta\\\\V=\int_0^{2\pi}\int_{\frac{\pi}{4}}^{\frac{3\pi}{4}} \sin \varphi \cdot \frac{64}{3} \, d\varphi\, d\theta\\\\V=\frac{64}{3} \int_0^{2\pi} [-\cos \varphi]_{\frac{\pi}{4}}^{\frac{3\pi}{4}}  \, d\theta\\\\V=\frac{64}{3} \int_0^{2\pi} \sqrt{2} \, d\theta\\\\

we get:

V=\frac{64}{3} \int_0^{2\pi} \sqrt{2} \, d\theta\\\\V=\frac{64\sqrt{2}}{3}\cdot[\theta]_0^{2\pi}\\\\V=\frac{128\sqrt{2}\pi}{3}

So,  the volume is:

\boxed{V=\frac{128\sqrt{2}\pi}{3}}

4 0
2 years ago
Two people apply for loans of the same amount. Due to differences in their credit scores, their payments differ by $72
kati45 [8]

Answer:

\large \boxed{\text{d) \$2592 }}

Step-by -step explanation:

The person with the lower credit score pays $72 more each month.

Over 36 mo, they will pay an extra

\text{Total amount} = \text{36 mo} \times \dfrac{\text{\$72}}{\text{1 mo}} = \textbf{\$2592}\\\\\text{The person with the lower credit score will have paid an extra $\large \boxed{\mathbf{\$2592 }}$}

7 0
3 years ago
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Step-by-step explanation: I know okie i jast want points

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2 years ago
Can someone help me with this problem. please
Kitty [74]

Answer:

Step-by-step explanation:

area = 30x + 30(x+3) + 30(2x)

= 30x + 30x+90 + 60x

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locust area = 30(2·5) = = 300 m²

8 0
2 years ago
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