In order to maximize the chances that experimental groups represent the population of interest, researchers should conduct random sampling and random group assignment
<u>Explanation:</u>
The terms Random sampling and Random group assignment are greatly different in process of the sample selection. The study related to the determination of how sample participants can be drawn from the population refers to the process of Random sampling. The sample participants are subjected to a treatment by the usage of a random procedure comprises the Random group assignment.
When a researcher wants validate externally then random selection can be used. When a researcher wants to determine the effects of treatment within that group which is known as determination of internal validity then he can opt for Random group assignment.
-3y + 4 + 5y = 2(y - 1)
2y + 4 = 2(y-1)
2y + 4 = 2y - 2
2y = 2y + 2
0
2
So this function has no answer
.08x+.05(15000-x)=930
.08x+750-.05=930
.08x-.05x=930-750
.03x=180
X=180/.03=6,000 at 8%
(15000-6000)=9000 at 5%
Answer:
I think its d
Step-by-step explanation:Because i think that.
Answer:
C. Kalena made a mistake in Step 3. The justification should state: -x²
+ x²
Step-by-step explanation:
Given the function x(x - 1)(x + 1) = x3 - X
To justify kelena proof
We will need to show if the two equations are equal.
Starting from the RHS with function x³-x
First we will factor out the common factor which is 'x' to have;
x(x²-1)
Factorising x²-1 using the difference of two square will give;
x(x+1)(x-1)
Note that for two real number a and b, the expansion of a²-b² using difference vof two square will give;
a²-b² = (a+b)(a-b) hence;
Factorising x²-1 using the difference of two square will give;
x(x+1)(x-1)
Factorising x(x+1) gives x²+x, therefore
x(x+1)(x-1) = (x²+x)(x-1)
(x²+x)(x-1) = x³-x²+x²-x
The function x³-x²+x²-x gotten shows that kelena made a mistake in step 3, the justification should be -x²+x² not -x-x²
