Treat x^4 as the square of p: x^4 = p^2.
Then x^4 - 5x^2 - 36 = 0 becomes p^2 - 5p - 36 = 0.
This factors nicely, to (p-9)(p+4) = 0. Then p = 9 and p = -4.
Equating 9 and x^2, we find that x=3 or x=-3.
Equating -4 and x^2, we see that there's no real solution.
Show that both x=3 and x=-3 are real roots of x^4 - 5x^2 - 36 = 0.
20 days
x=number of days vacation
y=daily expenses
xy=1100
(x+2)(y-5)=1100
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xy-5x+2y-10=1100
xy-5x+2y=1110
y=1100/x
x(1100/x)-5x+2(1100/x)=1110
1100-5x+(2200/x)=1110
-5x+(2200/x)=10
-5x^2 + 2200 = 10x
-x^2 + (440) = 2x
x^2 - 440 + 2x = 0
(x+22)(x-20)=0
x=-22,20
only take the positive answer because the negative answer doesn't make sense in the question
so the answer is 20
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I might be wrong; this question probation should've been this hard so I might have taken a wrong turn somewhere. feel free to double check my work
Answer:
B. g(x) = 3/4|x|
Step-by-step explanation:
Multiplying the function by a number in front will stretch, compress, and/or reflect the function over the x-axis.
So if the number in front is negative that will flip it upside down, over the x-axis.
If the number is greater than 1, the function will be vertically stretched, narrower, slimmer, skinnier, taller.
In this case, the graph is vertically compressed, making it flatter, fatter, wider smashed. In this case is where the number multiplied in front of the parent function is LESS than one.
g(x) = 3/4 |x|
Answer: All I'm seeing is a blank screen I'm sorry can you try it again?
I don't know the answer I need help on it as well
