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arlik [135]
2 years ago
6

Help ASAP for brainliest

Mathematics
1 answer:
irga5000 [103]2 years ago
6 0

Answer: D

Step-by-step explanation:

10+20=30

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9^2(x-1) = 27^x how do I solve this equation?
serg [7]
Answer: x = 2

Explanation: 9^2x-1 = 3^2 • (2x - 1) = 3^4x-2

27x = 3^3x

Upon equating: 3^4x-2 =3^3x

Since the base is equal , we can equate the powers:

4x - 2 = 3x
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2 years ago
Calculate the perimeter and area of the following square if a= 19
Licemer1 [7]

Formula for perimeter of a square: P = 4a

Formula for area of a square: A = a²

a is given as:

19

Plug this value for a into the above formulas to solve for perimeter and area.

P = 4a

P = 4(19)

P = 76

-----------------------------------------------------------------------------------------------------------------

A = a²

A = 19²

A = 361

Answer:

P = 76 units; A = 361 units².

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Find the measure of each angle.
Galina-37 [17]

<u>Given</u>:

Given that the isosceles trapezoid JKLM.

The measure of ∠K is 118°

We need to determine the measure of each angle.

<u>Measure of ∠L:</u>

By the property of isosceles trapezoid, we have;

\angle K+\angle L=180^{\circ}

118^{\circ}+\angle L=180^{\circ}

           \angle L=62^{\circ}

Thus, the measure of ∠L is 62°

<u>Measure of ∠M:</u>

By the property of isosceles trapezoid, we have;

\angle L \cong \angle M

Substituting the value, we get;

62^{\circ}=\angle M

Thus, the measure of ∠M is 62°

<u>Measure of ∠J:</u>

By the property of isosceles trapezoid, we have;

\angle J \cong \angle K

Substituting the value, we get;

\angle J =118^{\circ}

Thus, the measure of ∠J is 118°

Hence, the measures of each angles of the isosceles trapezoid are ∠K = 118°, ∠L = 62°, ∠M = 62° and ∠J = 118°

4 0
3 years ago
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