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LiRa [457]
3 years ago
14

The area of a rectangle is x^2+2x-24 Which of the following could be one of the dimensions?

Mathematics
1 answer:
Leno4ka [110]3 years ago
3 0

Answer: (x-4)

Step-by-step explanation:

x^2 + 8x +15 is the area

x+5 is the length

x+3 is the width

(x+5)(x+3)=

x^2 + 3x +5x +15

x^2 +8x + 15

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Joyce saved $70 on an item that was 75 % % off. What was the original price?
SashulF [63]

if Joyce saved $70

at 75% off, Joyce saved 25%

so, $70 is 25%

To find the total price which is 100%, multiply $70 by 4 ( because 25% x 4 = 100% )

so the original price is $70 x 4 = $280

4 0
3 years ago
Plot 9/10 and 1 2/5 on the number line below​
HACTEHA [7]
First one is 9/10 second is 1 2/5

6 0
3 years ago
3 An open cone has a vertical angle measuring 40°
belka [17]

Answer:

13.41 cm

Step-by-step explanation:

The radius, height, and HALF of vertical angle makes a triangle.

Where

Radius will be the base of the triangle

Height will be the "height" of the triangle

Top angle will be HALF of vertical angle (40/2 = 20)

From the 20 degree angle, the side "opposite" would be the radius, which is 30. The side "adjacent" would be the height, let it be h.

<em>Which trig ratio relates opposite and adjacent? Yes, that is TAN. Thus we can write:</em>

Tan(20) = opposite/adjacent

Tan(20) = 30/h

h = 30/Tan(20)

h = 13.41

So

The height of the cone would be around 13.41 cm

3 0
3 years ago
I’ll give brainliest
motikmotik

Answer:

v= 5/6

Step-by-step explanation:

You have to divide -6 on both sides to isolate the variable V. Then it would become -5/-6. The negative signs cancel out.

6 0
3 years ago
Read 2 more answers
What is an equation of the line that passes through point (5,-8) and is parallel to the line x+y=7
Igoryamba

Answer:

The line given is equal to y=-x+7 (Through rearranging)

To find the new line, we substitute the given coordinates (5,8) in the equation without the given y-intersect (+7):

-8=-5+c

c=-3

The line parallel to x+y=7 that passes through the point (5,-8) is y=-x-3

4 0
3 years ago
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