X = 0 ; y = 10 ; 10 = a(0) + b(0) + c
c = 10
x=2 ; y = 15 ; 15 = a(4) + b(2) + 10 ; 5 = 4a+2b
x=4 ; y=18 ; 18 = a(16) + b(4) + 10 ; 8 = 16a + 4b
2(5) = (4a+2b)2
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<u> 8 = 16a + 4b
</u> 2 = -8a
a = -0.25
b = 2
y = (1/4)x^2 + 2x + 10 ; 4y = x^2 + 8x + 40
You plug in 2x + 4 into the y for the other equation (3x +y ) and solve for it
Answer:
abt 36,469
Step-by-step explanation:
36468.75
estimate it to 36,469 bc .75 of rabbit is not possible
Answer:
a. it has no solution
b. you can only substitute by making either the 'x' or 'y' the subject of either of the two equations.
Step-by-step explanation:
3x - 9y = -13.............. eqn 1
x - 3y = -7................... eqn 2
from eqn 2
x - 3y = -7, substitute by making 'x' the subject
x = -7 + 3y.................. eqn 3
put eqn 3 into eqn 1
3x - 9y = -13
3( -7 + 3y) - 9y = -13
-21 + 9y - 9y = -13
9y - 9y = -13 + 21
0 = 8, which is not possible.
