Answer:
The simplified version of ![\sqrt[3]{135}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B135%7D)
is ![3\sqrt[3]{5}](https://tex.z-dn.net/?f=3%5Csqrt%5B3%5D%7B5%7D)
.
Step-by-step explanation:
The given expression is
According to the property of radical expression.
![\sqrt[n]{x}=(x)^{\frac{1}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%7D%3D%28x%29%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D)
Using this property we get
![\sqrt[3]{135}=(135)^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B135%7D%3D%28135%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
![\sqrt[3]{135}=(27\times 5)^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B135%7D%3D%2827%5Ctimes%205%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
![\sqrt[3]{135}=(3^3\times 5)^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B135%7D%3D%283%5E3%5Ctimes%205%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
![\sqrt[3]{135}=(3^3)^{\frac{1}{3}}\times (5)^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B135%7D%3D%283%5E3%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%5Ctimes%20%285%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
![[\because (ab)^x=a^xb^x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%28ab%29%5Ex%3Da%5Exb%5Ex%5D)
![\sqrt[3]{135}=3\times \sqrt[3]{5}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B135%7D%3D3%5Ctimes%20%5Csqrt%5B3%5D%7B5%7D)
![[\because \sqrt[n]{x}=(x)^{\frac{1}{n}}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Csqrt%5Bn%5D%7Bx%7D%3D%28x%29%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D%5D)
![\sqrt[3]{135}=3\sqrt[3]{5}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B135%7D%3D3%5Csqrt%5B3%5D%7B5%7D)
Therefore the simplified version of is .
try this for answer (11×3.5)-9=x
Answer:
A 3/5
Step-by-step explanation:Here’s one way to solve this problem.
Write sixty percent as a fraction having a denominator of one hundred.
Now, change sixty-hundredths to an equivalent fraction having a denominator of twenty, the total number of pitches.
Do this by dividing the numerator and the denominator by five.
Then, simplify the fraction twelve-twentieths by dividing the numerator and the denominator by four.
So, Lenora hit three-fifths of the pitches.
The table is linear because the change because it had a constant slope when we solve for change in y / change in x for each of the data points given. That slope is -0.5 and it’s constant.
