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3 years ago

What is the slope of Y=0?

1 answer:

3 0

The slope is 0!! any horizontal line, like y = 1, y = 2, y = any other number, has a slope of 0. because it's a horizontal line, it's flat, so there isn't any incline or decline. just as a note: vertical lines (x = 1, etc.) have an undefined slope.

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Jeremy is building a large deck for a community center. The deck is shaped as a rectangle. The width of the deck is 29 feet. The

GrogVix [38]

2x29+2x1 ≥ 134
2x1≥76
1≥76/2
1 ≥ 38

7 0

2 years ago

A fossil was analyzed and determined to have a carbon-14 level that is 80 % that of living organisms. the half-life of c-14 is 5

liq [111]

Answer:

The fossil is 1860 years old.

Step-by-step explanation:

The equation for the amount of fossil has the following format:

$Q(t) = Q(0)e^{rt}$

In which Q(t) is the amount after t years, Q(0) is the initial amount and r is the rate of change.

Half-life of c-14 is 5730 years.

This means that $Q(5730) = 0.5Q(0)$

$Q(t) = Q(0)e^{rt}$

$0.5Q(0) = Q(0)e^{5730r}$

$e^{5730r} = 0.5$

$\ln{e^{5730r}} = \ln{0.5}$

$5730r = \ln{0.5}$

$r = \frac{\ln{0.5}}{5730}$

$r = -0.00012$

$Q(t) = Q(0)e^{-0.00012t}$

How old is the fossil?

This is t for which

$Q(t) = 0.8Q(0)$

$Q(t) = Q(0)e^{-0.00012t}$

$0.8Q(0) = Q(0)e^{-0.00012t}$

$e^{-0.00012t} = 0.8$

$\ln{e^{-0.00012t}} = \ln{0.8}$

$-0.00012t = \ln{0.8}$

$t = -\frac{\ln{0.8}}{-0.00012}$

$t = 1860$

The fossil is 1860 years old.

4 0

2 years ago

HELP ME PLEASE IM SO DESPERATE TO ANSWER THIS, ILL BE SO THANKFUL TO YALL

Scrat [10]

Answer:

x+2 volts is what I got.

Step-by-step explanation:

7 0

2 years ago

I need help with solving a system of equations using elimination

Nataliya [291]

Answer:

do it your self.

Step-by-step explanation:

7 0

2 years ago

Chi works cutting lawns. Last week, he worked 34 hours and earned $329.12. What is his hourly wage?

Mila [183]

We want to find the number of dollars Chi makes for every hour he cuts lawns. This proportion would be dollars/hour.

329.12 / 34 = 9.68

Chi's hourly wage is $9.68 per hour.

Hope this helps!! :)

5 0

2 years ago