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Neporo4naja [7]

3 years ago

5

What is the slope of Y=0?

1 answer:

olganol [36]3 years ago

3 0

The slope is 0!! any horizontal line, like y = 1, y = 2, y = any other number, has a slope of 0. because it's a horizontal line, it's flat, so there isn't any incline or decline. just as a note: vertical lines (x = 1, etc.) have an undefined slope.

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Please help now with homework

damaskus [11]

The correct answer is 1.25 dollars per pound. You can check it by multiplying it with 4.16

5 0

2 years ago

Kelly pays $25/sweater wholesale.find the salling price if her mark-up is 65%?

gladu [14]

This is another way of saying what is 165% of 25, because 65% of the sweater is the markup, and you add the markup to the whole sale.
165% is 1.65 in decimal form, so $1.65*25=41.25$
$41.25$ is your answer

3 0

3 years ago

Solve 4x-2y=12 for y <br> Ayo help

Leni [432]

Answer:

y = - 6 + 2x

Step-by-step explanation:

Given

4x - 2y = 12 ( subtract 4x from both sides )

- 2y = 12 - 4x ( divide all terms by - 2 )

y = - 6 + 2x

4 0

2 years ago

Read 2 more answers

The numerator of a fraction is four less than the denominator. If 17 is added to each.

Mkey [24]

Answer:

x + 13 / x + 17

Step-by-step explanation:

x - 4 / x

x + 13 / x + 17

4 0

1 year ago

If the ratio of the length of segment AC to the length of segment CB is 3:1, what is the y-coordinate of point C?

Yuki888 [10]

Answer:

The coordinates of point C are (8,8.5)

Step-by-step explanation:

The picture of the question in the attached figure

Let

$(C_x,C_y)$ ----> coordinates of point C

we have that

The horizontal distance AB is equal to

$AB_x=10-2=8\ units$

The vertical distance AB is equal to

$AB_y=10-4=6\ units$

Find the horizontal coordinate of point C

we know that

$\frac{AC}{CB}=\frac{3}{1}$

so

$\frac{AC_x}{CB_x}=\frac{3}{1}$

$AC_x=3CB_x$ ----> equation A

$AC_x+CB_x=8$ ----> equation B

substitute equation A in equation B

$3CB_x+CB_x=8$

$4CB_x=8\\CB_x=2$

$AC_x=3(2)=6$

so

The x-coordinate of point C is equal to the x-coordinate of point A plus the horizontal distance between the point A and point C

$C_x=A_x+AC_x=2+6=8$

Find the vertical coordinate of point C

we know that

$\frac{AC}{CB}=\frac{3}{1}$

so

$\frac{AC_y}{CB_y}=\frac{3}{1}$

$AC_y=3CB_y$ ----> equation A

$AC_y+CB_y=6$ ----> equation B

substitute equation A in equation B

$3CB_y+CB_y=6$

$4CB_y=6\\CB_y=1.5$

$AC_y=3(1.5)=4.5$

so

The y-coordinate of point C is equal to the y-coordinate of point A plus the vertical distance between the point A and point C

$C_y=A_y+AC_y=4+4.5=8.5$

therefore

The coordinates of point C are (8,8.5)

5 0

2 years ago