Answer:
95% confidence for µ, the average number of times a horse races
(12.493 , 18.107)
Step-by-step explanation:
<u>Explanation</u>:-
The veterinarian finds that the average number of races a horse enters is 15.3
The mean of the sample x⁻ = 15.3
Given standard deviation of the sample 'S' = 6.8
Given sample size 'n' = 25
Degrees of freedom = n-1 =25-1 =24
The tabulated value 't' = 2.064 at two tailed test 0.95 level of significance
<u> 95% confidence for µ, the average number of times a horse races</u>
<u></u>
<u></u>
<u></u>
<u></u>
(15.3 - 2.80704 ,15.3 +2.80704)
(12.493 , 18.107)
<u>Conclusion</u>:-
95% confidence for µ, the average number of times a horse races
(12.493 , 18.107)
Answer:
90
Step-by-step explanation:
*One half of two fifths of x.
Answer:
Criteria for my Cup:
I want my cup to be short and wide.
Step-by-step explanation:
a) By the way, a cup can be measured in volume. There are no tall and skinny cups. They are not attributes of a cup. However, a cup can be short (height). It can also be wide, usually measured in diameter and radius.
b) Data:
Volume cubic centimeters milliliters fluid ounces cups
cold pack 150 150 5 0.6
drink compartment 600 600 20 2.5
total 750 750 25 3.1
2) 1.2 x 10,000 - 1.5 x 1,000 - 2.2 x 100 = 10,280
3) 7.3 x 100,000 + 1.6 x 1,000,000 + 4.7 x
100,000 = 2,800,000
4) 8.2 x 10,000 - 2.4 x 10,000 - 1.5 x 1,000 = 56,500
5) 2.4 x 1,000 + 3.4 x 10,000 + 1.5 x 1,000 = 37,900
6) 6.2 x 10,000 - 3.4 x 100 - 7.5 x 1,000 = 54,160
7) 8.3 x 100,000 + 1.6 x 10,000,000 + 6.7 x 10,000 = 16,897,000
8) 8.0 x 1,000 - 0.8 x 1,000 - 1.2 x 100 = 7,080
16 oz es 1 lb
12 in es 1ft
2 c es 1pt
3 ft es 1 yd
1mi es 5280 ft
8 fl oz es 1 c
2pt es t qt
1 T es 2000 lb
