A balloon was release and went straight up 3 miles and then the wind blew it 6 miles east. What is the balloon's diagonal back t
1 answer:
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Answer: B: (1-5x²)³, all real numbers
Step-by-step explanation:
The notation is called function composition, which is where you pass one function in as the value of another function. In other words,
.
Since we have the values for f(x) and g(x), let's plug them in.
Hence, the best answer choice is B, as all real numbers would work and it is the cube of 1 - 5x².
Given points are P(4,m) and Q(-2,4)
Let (x1, y1) = P(4,m)
Where, • x1 = 4 and • y1 = m
Let (x2, y2) = Q(-2,4)
Where, • x2 = -2 and • y2 = 4
We know that
The coordinates of the mod point of the linesegment joining the points (x1, y1) and (x2, y2)
is M(x,y) = ( {x1+x2}/2 , {y1+y2}/2 )
Mid point of the linesegment PQ
⇛M(x,y) = ( { 4+(-2)}/2 ,{m+4}/2)
⇛M(x,y) = {(4-2)/2 , {m+4}/2)
⇛M(x,y) = (2/2,{m+4}/2)
⇛M(x,y) = (1,{m+4}/2)
According to the given problem
Mid point of PQ = C(n,-1)
M(x,y) = C(n,-1)
(1,{m+4}/2) = (n,-1)
On Comparing both sides then
1 = n and (m+4)/2 = -1
n = 1 and m+4 = -2
n = 1 and m = -2-4
n = 1 and m = -6
Hence, the value of m&n will be (1&-6) respectively.
<em>Additional</em><em> comment</em><em>:</em>
The coordinates of the mod point of the linesegment joining the points (x1, y1) and (x2, y2)
is M(x,y) = ( {x1+x2}/2 , {y1+y2}/2 )
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