2 years ago

What is the perimeter, in units of a polygon with vertices located at (-7, -3), (-7, 4) , (6, -3), and (6, 4)?

1 answer:

4 0

Answer:

40 units

Step-by-step explanation:

-7 to 6 is 13 units and -3 to 4 is 7 units, it asks for perimeter so 13 x 2 + 7 × 2

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vova2212 [387]

It is given in the question that

M is the MIDPOINT OF FG.

$FG = 26 \ AND \ GM = (3X - 2)$

Since M is the midpoint of FG, therefore GM is half of FG. That is

$3X-2 = \frac{1}{2} (26)$

$3X-2 =13
\\
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\\
X =5$

Therefore

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And FM is 13 too .

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Usimov [2.4K]

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3 years ago

nevsk [136]

180-34=146
146-5=141
ratio=1:4
1+4=5
141÷5=28.2
x=28.2
y=112.8

I may be wrong, ask for more opinions
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--- O
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3 years ago