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lutik1710 [3]
3 years ago
5

Which measurement is most accurate to describe the amount that a teacup can hold?

Mathematics
2 answers:
Anni [7]3 years ago
5 0
ML milliliters  hope that helps

eduard3 years ago
4 0
Milliliters, they aren't the absolute smallest but they are still small since a teacup is small.. hope I helped:)
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Please helps
lisabon 2012 [21]

Answer: A. f(n) = 4 ∙ 2n-1

Step-by-step explanation:

because the 1st term is 4 according to your image, and then you will have to multiply that by its common difference and using your table, to get from 4 to 8 then 8 to 16 you would multiply by 2, and you would finally multiply that by n or known as the number of terms and 1 making the equation. f(n) = 4 ∙ 2n-1 I hope this is very helpful for everyone.

5 0
3 years ago
HELP WILL GIVE BRAINLIEST
mina [271]

Answer:

38° po siya

HOPE IT HELPS

6 0
2 years ago
The product of 5 and a number n is at least 25
Crazy boy [7]
5n≥25
and if you divide 5 on both sides, n≥5 (I don't know if you are supposed to solve or simply put it in the equation form).

Product refers to multiplication. so 5 and n are being multiplied in the equation.
However, instead of using an equal sign, the sign for "greater than or equal to" must be used. "At least" is a term equivalent to "greater than or equal to".
4 0
3 years ago
The differential equation y′′=0 has one of the following two parameter families as its general solution: yyyy=C1ex+C2e−x=C1cos(x
svet-max [94.6K]

Answer:

y_c = 2 + 10*x

Step-by-step explanation:

Given:

                                                y'' = 0

Find:

- The solution to ODE such that y(0) = 2, y'(0) = 10

Solution:

- Assuming a solution y = Ce^(mt)

So,                                y' = C*me^(mt)

                                    y'' = C*m^2e^(mt)

- Back substitute into given ODE, we get:

                                    y'' = C*m^2e^(mt) = 0

                                    e^(mt) can not be equal to zero

- Hence,                       m^2 = 0

                                     m = 0 , 0 - (repeated roots)

- The complimentary function for repeated roots is:

                                    y_c = (C1 + C2*x)*e^(m*t)

                                    y_c = C1 + C2*x  

- Evaluate @ y(0) = 2

                                    2 = C1 + C2*0

                                    C1 = 2

-Evaluate @ y'(0) = 10

                                    y'(t) = C2 = 10

Hence,                         y_c = 2 + 10*x

5 0
3 years ago
Need help ASAP
masha68 [24]

Answer:

y=1/2x-8

Step-by-step explanation:

the slope is 1 over 2

5 0
3 years ago
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