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1 year ago

Brainliest if you show how to do the work

Mathematics

2 answers:

OleMash [197]1 year ago

7 0

Give them brainiest

solong [7]1 year ago

3 0

Answer:

26.376 because the circumference formula is 2*3.14*radius so the radius of the goal would be 9 because radius is half of diameter which is 18 so 2*3.14*9=56.52 and the basketball's radius would be 4.8 and then 2*3.14*4.8 is 30.144 so the answer is 26.376 hope it helps

Step-by-step explanation:

Please can I have the brainliest

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Luke bought 256256256 ounces of strawberries. He divided them evenly between 888 different pies. How many pounds of strawberries

SIZIF [17.4K]

Answer:

2 pounds.

Step-by-step explanation:

We have been given that Luke bought 256 ounces of strawberries. He divided them evenly between 8 different pies. We are asked to find the pounds of strawberries that Luke put on each pie.

First of all, we will convert 256 ounces into pounds.

We know that 1 pound equals 16 ounces. To convert 256 ounces into pounds, we need to divide 256 by 16.

$\text{256 ounces}=\frac{256}{16}\text{ pounds}=16\text{ pounds}$

Now we will divide 16 pounds by 8 to find number of strawberries put on each pie.

$\text{Pounds of strawberries on each pie}=\frac{16}{8}$

$\text{Pounds of strawberries on each pie}=2$

Therefore, Luke put 2 pounds strawberries on each pie.

4 0

3 years ago

Help me asap!!!!!!!!!!!

melisa1 [442]

Answer:

(x-2)^2-11

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

The mean number of words per minute (WPM) read by sixth graders is 8888 with a standard deviation of 1414 WPM. If 137137 sixth g

Bingel [31]

Noticing that there is a pattern of repetition in the question (the numbers are repeated twice), we are assuming that the mean number of words per minute is 88, the standard deviation is of 14 WPM, as well as the number of sixth graders is 137, and that there is a need to estimate the probability that the sample mean would be greater than 89.87.

Answer:

"The probability that the sample mean would be greater than 89.87 WPM" is about $\\ P(z>1.56) = 0.0594$ .

Step-by-step explanation:

This is a problem of the distribution of sample means. Roughly speaking, we have the probability distribution of samples obtained from the same population. Each sample mean is an estimation of the population mean, and we know that this distribution behaves normally for samples sizes equal or greater than 30 $\\ n \geq 30$ . Mathematically

$\\ \overline{X} \sim N(\mu, \frac{\sigma}{\sqrt{n}})$ [1]

In words, the latter distribution has a mean that equals the population mean, and a standard deviation that also equals the population standard deviation divided by the square root of the sample size.

Moreover, we know that the variable Z follows a normal standard distribution, i.e., a normal distribution that has a population mean $\\ \mu = 0$ and a population standard deviation $\\ \sigma = 1$ .

$\\ Z = \frac{\overline{X} - \mu}{\frac{\sigma}{\sqrt{n}}}$ [2]

From the question, we know that

The population mean is $\\ \mu = 88$ WPM
The population standard deviation is $\\ \sigma = 14$ WPM

We also know the size of the sample for this case: $\\ n = 137$ sixth graders.

We need to estimate the probability that a sample mean being greater than $\\ \overline{X} = 89.87$ WPM in the distribution of sample means. We can use the formula [2] to find this question.

The probability that the sample mean would be greater than 89.87 WPM

$\\ Z = \frac{\overline{X} - \mu}{\frac{\sigma}{\sqrt{n}}}$

$\\ Z = \frac{89.87 - 88}{\frac{14}{\sqrt{137}}}$

$\\ Z = \frac{1.87}{\frac{14}{\sqrt{137}}}$

$\\ Z = 1.5634 \approx 1.56$

This is a standardized value and it tells us that the sample with mean 89.87 is 1.56 standard deviations above the mean of the sampling distribution.

We can consult the probability of P(z<1.56) in any cumulative standard normal table available in Statistics books or on the Internet. Of course, this probability is the same that $\\ P(\overline{X} < 89.87)$ . Then

$\\ P(z$

However, we are looking for P(z>1.56), which is the complement probability of the previous probability. Therefore

$\\ P(z>1.56) = 1 - P(z$

$\\ P(z>1.56) = P(\overline{X}>89.87) = 0.0594$

Thus, "The probability that the sample mean would be greater than 89.87 WPM" is about $\\ P(z>1.56) = 0.0594$ .

5 0

2 years ago

Several factors influence the size of the F-ratio. For each of the following, indicate whether it would influence the numerator

enyata [817]

Answer:

(a) Increase the differences between the sample means this will increase the Numerator.

(b) Increase the sample variances will increase the denominator.

Step-by-step explanation:

F Ratio = Variance between treatments/ Variance within treatments.

Here,

(a) Increase the differences between the sample means:

- Will increase the Numerator and

- Size of the F-ratio would increase

(b) Increase the sample variances:

- Will increase the denominator and

- Size of the F Ratio would decrease.

8 0

2 years ago

A recycling bin is in the shape of a right rectangular prism. The bin is 12 meters long, 512 meters wide, and 612 meters tall.

devlian [24]

To find the volume of the recycling bin, you will use the formula for finding volume of a rectangular prism.

V = lwh
V = 12 x 512 x 612
V = 3760128 cubic meters

The answer is not given, but based in these numbers this is correct.

If it is 12 m x 5 m x 6 than the answer is 360 cubic meters

6 0

2 years ago