divide the numerator and denominator by 13
=
<span>3^2 + 4^2 = 5^2
answer is </span>A) 3^2 + 4^2 = 5^2
1 - 2/3 - 1/4
= 1 - 8/12 - 3/12
= 1/12
Given that the arc length is 4.189 cm and the radius is 3 cm, the size of the arc will found as follows;
C=theta/360 πd
suppose:
size of arc=theta=x
d=3*2=6 cm
hence;
4.189=x/360*π*6
4.189=0.0524x
x=4.189/0.0524
x=80.004°
The size of the arc length is 80.004°
