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yKpoI14uk [10]
2 years ago
11

Please help now Pic below

Mathematics
1 answer:
olga nikolaevna [1]2 years ago
6 0
D represents where the market will be located and how far from each point
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Geometry B Final Exam
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The answer is 54 degrees I took the exam I got it right

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2 years ago
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muhammad, a shipping and receiving clerk uses 1 yard, 2 feet and 4 inches Of twine to wrap each carton he packs. he has to pack
antiseptic1488 [7]

Answer:

<em>He will need 51 yards, 1 foot and 8 inches twine to wrap 29 cartons. </em>

Step-by-step explanation:

Muhammad uses 1 yard, 2 feet and 4 inches of twine to wrap each carton he packs.

<u>We know that, 1 yard = 36 inches and 1 foot = 12 inches</u>.

So,  1 yard, 2 feet and 4 inches =[(1*36)+(2*12)+4]inches = 64 inches.

That means, he uses 64 inches of twine to wrap each carton.

He has to pack 29 cartons today. So, <u>the total length of the twine he will need</u>  =(64*29) inches= 1856 inches.

Now....

1856 inches

=\frac{1856}{36} yards \\ \\= 51 \frac{5}{9} yards \\ \\= 51 yards+(\frac{5}{9}*36)inches \\ \\= 51 yards, 20 inches \\ \\= 51 yards, (12+8)inches \\ \\=51 yards, 1 foot, 8 inches.

Thus, he will need 51 yards, 1 foot and 8 inches twine to wrap 29 cartons.

8 0
3 years ago
United Blood Services is a blood bank that serves more than 500 hospitals in 18 states. According to their website, a person wit
Anna11 [10]

Answer:

a) 0.06 = 6% probability that a person has both type O blood and the Rh- factor.

b) 0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.

Step-by-step explanation:

I am going to solve this question treating these events as Venn probabilities.

I am going to say that:

Event A: Person has type A blood.

Event B: Person has Rh- factor.

43% of people have type O blood

This means that P(A) = 0.43

15% of people have Rh- factor

This means that P(B) = 0.15

52% of people have type O or Rh- factor.

This means that P(A \cup B) = 0.52

a. Find the probability that a person has both type O blood and the Rh- factor.

This is

P(A \cap B) = P(A) + P(B) - P(A \cup B)

With what we have

P(A \cap B) = 0.43 + 0.15 - 0.52 = 0.06

0.06 = 6% probability that a person has both type O blood and the Rh- factor.

b. Find the probability that a person does NOT have both type O blood and the Rh- factor.

1 - 0.06 = 0.94

0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.

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2 years ago
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Nookie1986 [14]

this picture would help you man stay strong

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3 years ago
K + 22 = 29<br> Solve the equation.
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<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em>⤴</em>

<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em>

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