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Aleks [24]
2 years ago
10

Plsssssssssssssssssss

Mathematics
2 answers:
sesenic [268]2 years ago
8 0

Answer:

18.6cm

Step-by-step explanation:

there is a theorem that states that the midsegment of a triangle (midpoint to midpoint, in this case X and Y) is half of the base (in this case BC)

when applied to the triangle shown:

XY= 1/2 BC

substitute to get

XY=1/2*6.4

XY=3.2

perimeter of BCYX

=XY+YC+CB+BX

=3.2+4+6.4+5

=18.6cm

hope this helps

n200080 [17]2 years ago
7 0
The answer is 18.6 cm
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A company has developed a training procedure to improve scores on the SAT. Following the training, 100 high school students take
Pani-rosa [81]

Answer:

The calculated t-test = 1.717 < 1.6604 at 0.05 level of significance

Null hypothesis is accepted at 0.05 level of significance

A company has developed a training procedure is significantly improve scores

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given  sample mean (x⁻ )  = 517

sample standard deviation (s) =90

Mean of the Population (μ) =500

<em>Null Hypothesis :- H₀ :  </em> (μ) =500

Alternative Hypothesis : H₁ :  μ ≠ 500

<u><em>Step(ii)</em></u>:-

Test statistic

                         t = \frac{x^{-} -mean}{\frac{s}{\sqrt{n} } }

                        t = \frac{517 -500}{\frac{90}{\sqrt{100} } }

                        t  =   1.717

<em>Level of significance</em>

                      ∝ = 0.05

                    t₀.₀₅ = 1.6604

The calculated t-test = 1.717 < 1.6604 at 0.05 level of significance

<u><em>Conclusion</em></u>:-

Null hypothesis is accepted at 0.05 level of significance

A company has developed a training procedure is significantly improve scores

3 0
2 years ago
In a certain town, the amount of sulfur oxide in the air, S, in tons, is related to the town’s population, P, in people. The rel
Lady bird [3.3K]

Answer:

Change in sulfur oxide in the air = \frac{\textup{110010}}{\textup{S}}

Step-by-step explanation:

Data provided in the question:

Relation between the amount of sulfur oxide in the air and the population as:

S² = 110P² + 20P + 600

Population growth rate, \frac{\textup{dP}}{\textup{dt}}  = 10 people per month

Now,

change in sulfur oxide with time i.e \frac{\textup{dS}}{\textup{dt}}

differentiating the given relation with respect to time 't'

we have

2S\frac{\textup{dS}}{\textup{dt}} =  2\times110P\frac{\textup{dP}}{\textup{dt}}  + 20

at P = 100 and  \frac{\textup{dP}}{\textup{dt}}  = 10 people per month

we have

2S\frac{\textup{dS}}{\textup{dt}} = 2 × 110 × 100 × 10 + 20

or

2S\frac{\textup{dS}}{\textup{dt}} = 220020

or

\frac{\textup{dS}}{\textup{dt}} = \frac{\textup{220020}}{\textup{2S}}

or

Change in sulfur oxide in the air = \frac{\textup{110010}}{\textup{S}}

8 0
2 years ago
I need the surface area again plz
kolezko [41]

Answer:

31

Step-by-step explanation:

A=2(wl+hl+hw)

l -Length  

w-Width  

h-Height

A=2(wl+hl+hw)=2·(1·2+4.5·2+4.5·1)=31

8 0
2 years ago
What is the area to this? (number 4)
IrinaK [193]
Use the formula 1/2(base1+base2)height. Substitute the values. 
7 0
3 years ago
Val has a piece of wood 8 ft long. She is going to cut it into 9 equal-length pieces.
Semenov [28]
Each piece will be 1/9 of the total length of the original board.

1/9 of 8 ft is <em>8/9 foot</em>.

That's the same as <em>(10 and 2/3) inches</em>.
5 0
3 years ago
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