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Nitella [24]
3 years ago
11

If f(x)=(2x)^2 find f(-4)

Mathematics
1 answer:
Reptile [31]3 years ago
5 0

Answer:

64

Step-by-step explanation:
1. Plug it in:

(2(-4))^2

2 times -4 is -8

(-8)^2 = 64

So there’s your answer

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Determine whether the statement is true or false, and explain why.
Sedbober [7]

Answer:

True

Step-by-step explanation:

The integral

\int\limits^1_0 {xe^{10x}} \, dx

in the integral we have a product of a monomial: x

and an exponential function: e^{10x}

In general case, when we have a combination of these two things you can use the integration by parts, where x will be u and e^{10x} will be dv.

The statement is true

3 0
3 years ago
10) HELP I have the answer I just need to show the work
bogdanovich [222]

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A) inverse sine is correct

6 0
3 years ago
Find the slope and the y-intercept of the line
Vinvika [58]

The slope is basically the coefficient of x and that is 1 since 1x=x. To find the y-intercept, you need to subtitute x=0 into y=x+5 because x is at 0 when you are looking at the y-intercept.

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6 0
4 years ago
(x^2−x−6x^2−8x+16)/(x2−x−12)
erma4kov [3.2K]

-3 and 4 cannot be the values of x in the given expression

The expression is given as:

\frac{(x^2-x-6x^2-8x+16)}{(x^2-x-12)}

Start by equating the denominator to 0

x^2 - x - 12 = 0

Expand the above equation

x^2 - 4x + 3x - 12 = 0

Factorize the equation

x(x - 4) + 3(x - 4) = 0

Factor out x - 4

(x + 3) (x - 4) = 0

Split

(x + 3)= 0\ or\  (x - 4) = 0

Remove brackets

x + 3= 0\ or\  x - 4 = 0

Solve for x

x =- 3\ or\  x = 4

Hence, -3 and 4 cannot be the value of x in the given expression

Read more about expressions at:

brainly.com/question/2972832

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I believe it’s A! because they would be wanting to control their new subjects that’s where dominating comes in
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