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adelina 88 [10]
2 years ago
5

Having some trouble with this question, any help? A wire supporting a radio tower is secured to the ground 14 m from the base of

the tower. If the angle between the ground and the wire is 57°, what is the height of the tower, to the nearest tenth of a metre?
Mathematics
1 answer:
Lera25 [3.4K]2 years ago
8 0

By using what we know about right triangles, we will see that the height is 11.7 m.

<h3>How to find the height of the tower?</h3>

We can view this as a right triangle, such that the wire is the hypotenuse of said triangle.

We know that the hypotenuse measures 14 m, and the angle between the ground and the wire si 57°. The height would be the opposite cathetus to that angle, so we can use the rule:

Sin(a) = (opposite cathetus)/hypotenuse

Replacing the values we get:

Sin(57°) = H/14m

Sin(57°)*14m = H = 11.7m

The height of the tower is 11.7 meters.

If you want to learn more about right triangles, you can read:

brainly.com/question/2217700

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Answer:

Step-by-step explanation:

75x + -300 = 25x + 200

Reorder the terms:

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Reorder the terms:

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Solving

-300 + 75x = 200 + 25x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-25x' to each side of the equation.

-300 + 75x + -25x = 200 + 25x + -25x

Combine like terms: 75x + -25x = 50x

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Combine like terms: 25x + -25x = 0

-300 + 50x = 200 + 0

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Add '300' to each side of the equation.

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Combine like terms: -300 + 300 = 0

0 + 50x = 200 + 300

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Combine like terms: 200 + 300 = 500

50x = 500

Divide each side by '50'.

x = 10

Simplifying

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