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2 years ago

Isaac keeps track of the amount of money in his savings certificate each month. He has accumulated the following data:

Mathematics

1 answer:

Dafna1 [17]2 years ago

3 0

Answer:

d. The common ratio is 1.1

Step-by-step explanation:

To see if the data has a common ratio or common difference, we have to see if the division between them is equal(common ratio), or if the difference between them is equal(common difference).

In this case, since $60.5 - 55 \neq 55 - 50$ , it has a common ratio.

To find it, we divide consecutive terms. For example:

$\frac{55}{50} = 1.1$

So the correct answer is:

d. The common ratio is 1.1

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Each year lizzy e's school purchases students agenda books, which are sold in the school store.This year, the school purchased 3

notsponge [240]

In order to make back the money they spent ($1,137.50) plus $1500, they want to make $1137.5+1500=2637.5$ $2,637.50 total.

They want to make this amount by selling 350 agendas, so divide the amount they want to make by 350 to find the amount per book:
$2637.5/350=7.54$
I rounded the answer to the nearest hundredth because the hundredth is the smallest amount we have in USD (the penny.)
So they need to charge at least $7.54 to make back their money plus $1500.

Hope I helped, and let me know if you have any questions :)

5 0

2 years ago

PLEASE HELP ME! find the measure of each numbered angle. pls

zzz [600]

Answer: ∠1 = 37.5°; ∠2 = 37.5°; ∠3 = 133°.

Step-by-step explanation:

∠1 = ∠2 = (180° - 105°) ÷ 2 = 37.5°

∠3 = 180° - 23° - 24° = 133°

3 0

2 years ago

(-6x - 8) - (8x-9) can you subtract the expressions

Tcecarenko [31]

Answer:

-14x+1

Step-by-step explanation:

-6x-8

-8x+9

-14x+1

4 0

2 years ago

Directions: Match the product and quotients estimates below with the correct expression on the left

prohojiy [21]

Answer:

Answer is in attached image.

Step-by-step explanation:

Given the expressions, for which we have to find the estimates as per the expressions on the left.

The given expressions are:

1) 35 $\times$ 23

2) 132 $\div$ 168

3) 17.3 $\times$ 18.4

4) 999 $\div$ 208

5) 998 $\times$ 211

Here, we need to find the rounded off numbers.

35 can be rounded to 40 and 23 to 20.

Therefore, equivalent to 35 $\times$ 23 is 40 $\times$ 20

132 can be rounded to 130 and 168 to 170.

Therefore, equivalent to 132 $\div$ 168 is 130 $\div$ 170.

17.3 can be rounded to 17.0 and 18.4 to 18.0.

Therefore, equivalent to 17.3 $\times$ 18.4 is 17.0 $\times$ 18.0.

999 can be rounded to 1000 and 208 to 210.

Therefore, equivalent to 999 $\div$ 208 is 1000 $\div$ 210.

998 can be rounded to 1000 and 211 to 210.

Therefore, equivalent to 998 $\times$ 211 is 1000 $\times$ 210.

The solution can be found in the attached image as well.

8 0

2 years ago

A membership committee of three is formed from four eligible members. Let the eligible members be represented by A, B, C, and D.

yKpoI14uk [10]

The correct statement is:

There are four ways to choose the committee.
There are three ways to form the committee if person D must be on it.
If persons B and C must be on the committee, there are two ways to form the committee.

It is given that:

A membership committee of three is formed from four eligible members.

1) There are four ways to choose the committee.

This statement is true.

Since we have to choose 3 members out of the 4 members so we can use the method of combination.

2) There are three ways to form the committee if person D must be on it.

This statement is also true.

Since D has to be in the committee, this means we have to choose 2 more people out of the three people to form the committee.

3) If seven members are eligible next year, then there will be fewer combinations.

This statement is wrong.

Since we have to choose 3 members out of 7 members so the number of possible combinations will be:

There are 35 combinations possible.

4) If persons B and C must be on the committee, there are two ways to form the committee.

If B and C have to be in the committee then we have to choose just one person out of the two people left.

Hence, the statement is true.

5) If persons A and C must be on the committee, then there is only one way to form the committee.

If A and C have to be on the committee then as in the last option we have to choose any one of the two-person left.

So possible number of ways is 2.

Hence, the statement is false.

Learn more about committee here: brainly.com/question/425830

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Your question is incomplete. Please read below to find the missing content.

A membership committee of three is formed from four eligible members. Let the eligible members be represented by A, B, C, and D. The possible outcomes include S = {ABC, ABD, ACD, BCD}.

Which statements about the situation are true? Check all that apply.

There are four ways to choose the committee.

There are three ways to form the committee if person D must be on it.

If seven members are eligible next year, then there will be fewer combinations.

If persons B and C must be on the committee, there are two ways to form the committee.

If persons A and C must be on the committee, then there is only one way to form the committee.

8 0

1 year ago