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2 years ago

4 divided by 1/3 is 12 becuase

Mathematics

1 answer:

Alex17521 [72]2 years ago

8 0

Answer:

Step-by-step explanation:

When we divide fractions we multiply instead since it's the opposite of division and we do the reciprocal. Reciprocal means we flip the fraction from 1/3 to 3/1

So:

4÷1/3 would become 4×3/1

4×3/1 is the same as 4×3

So:

4×3=12

That's why the answer is 12.

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Evaluate the line integral by the two following methods. xy dx + x2 dy C is counterclockwise around the rectangle with vertices

Airida [17]

Answer:

25/2

Step-by-step explanation:

Recall that for a parametrized differentiable curve C = (x(t), y(t)) with the parameter t varying on some interval [a, b]

$\large \displaystyle\int_{C}[P(x,y)dx+Q(x,y)dy]=\displaystyle\int_{a}^{b}[P(x(t),y(t))x'(t)+Q(x(t),y(t))y'(t)]dt$

Where P, Q are scalar functions

We want to compute

$\large \displaystyle\int_{C}P(x,y)dx+Q(x,y)dy=\displaystyle\int_{C}xydx+x^2dy$

Where C is the rectangle with vertices (0, 0), (5, 0), (5, 1), (0, 1) going counterclockwise.

a) Directly

Let us break down C into 4 paths $\large C_1,C_2,C_3,C_4$ which represents the sides of the rectangle.

$\large C_1$ is the line segment from (0,0) to (5,0)

$\large C_2$ is the line segment from (5,0) to (5,1)

$\large C_3$ is the line segment from (5,1) to (0,1)

$\large C_4$ is the line segment from (0,1) to (0,0)

Then

$\large \displaystyle\int_{C}=\displaystyle\int_{C_1}+\displaystyle\int_{C_2}+\displaystyle\int_{C_3}+\displaystyle\int_{C_4}$

Given 2 points P, Q we can always parametrize the line segment from P to Q with

r(t) = tQ + (1-t)P for 0≤ t≤ 1

Let us compute the first integral. We parametrize $\large C_1$ as

r(t) = t(5,0)+(1-t)(0,0) = (5t, 0) for 0≤ t≤ 1 and

r'(t) = (5,0) so

$\large \displaystyle\int_{C_1}xydx+x^2dy=0$

Now the second integral. We parametrize $\large C_2$ as

r(t) = t(5,1)+(1-t)(5,0) = (5 , t) for 0≤ t≤ 1 and

r'(t) = (0,1) so

$\large \displaystyle\int_{C_2}xydx+x^2dy=\displaystyle\int_{0}^{1}25dt=25$

The third integral. We parametrize $\large C_3$ as

r(t) = t(0,1)+(1-t)(5,1) = (5-5t, 1) for 0≤ t≤ 1 and

r'(t) = (-5,0) so

$\large \displaystyle\int_{C_3}xydx+x^2dy=\displaystyle\int_{0}^{1}(5-5t)(-5)dt=-25\displaystyle\int_{0}^{1}dt+25\displaystyle\int_{0}^{1}tdt=\\\\=-25+25/2=-25/2$

The fourth integral. We parametrize $\large C_4$ as

r(t) = t(0,0)+(1-t)(0,1) = (0, 1-t) for 0≤ t≤ 1 and

r'(t) = (0,-1) so

$\large \displaystyle\int_{C_4}xydx+x^2dy=0$

$\large \displaystyle\int_{C}xydx+x^2dy=25-25/2=25/2$

Now, let us compute the value using Green's theorem.

According with this theorem

$\large \displaystyle\int_{C}Pdx+Qdy=\displaystyle\iint_{A}(\displaystyle\frac{\partial Q}{\partial x}-\displaystyle\frac{\partial P}{\partial y})dydx$

where A is the interior of the rectangle.

so A={(x,y) | 0≤ x≤ 5, 0≤ y≤ 1}

We have

$\large \displaystyle\frac{\partial Q}{\partial x}=2x\\\\\displaystyle\frac{\partial P}{\partial y}=x$

$\large \displaystyle\iint_{A}(\displaystyle\frac{\partial Q}{\partial x}-\displaystyle\frac{\partial P}{\partial y})dydx=\displaystyle\int_{0}^{5}\displaystyle\int_{0}^{1}xdydx=\displaystyle\int_{0}^{5}xdx\displaystyle\int_{0}^{1}dy=25/2$

3 0

3 years ago

8x - (2x - 13) = 42 solve and check the equation

pantera1 [17]

Answer:

x = 29/6

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Distributive Property

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Terms/Coefficients

Step-by-step explanation:

Step 1: Define

Identify

8x - (2x - 13) = 42

Step 2: Solve for x

[Distributive Property] Distribute negative: 8x - 2x + 13 = 42
[Subtraction] Combine like terms: 6x + 13 = 42
[Subtraction Property of Equality] Subtract 13 on both sides: 6x = 29
[Division Property of Equality] Divide 6 on both sides: x = 29/6

Step 3: Check

Plug in x into the original equation to verify it's a solution.

Substitute in x: 8(29/6) - [2(29/6) - 13] = 42
Multiply: 116/3 - [29/3 - 13] = 42
[Brackets] Subtract: 116/3 - -10/3 = 42
Subtract: 42 = 42

Here we see 42 does indeed equal 42.

∴ x = 29/6 is the solution.

7 0

3 years ago

Read 2 more answers

Percent of change from 125cm to 87.5cm

VikaD [51]

Percent Change from 125cm to 87.5cm

% Change = (87.5 - 125) / 125 * 100%

   = -37.5 / 125 * 100%

   = -0.3 * 100%

   = -30 %

The percent change is -30 % or 30% decrease.

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3 years ago

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zhuklara [117]

Answer:

The answer is d

Step-by-step explanation:

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3 years ago

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42.Anna pours herself some room-temperature soda from a bottle and adds four ice cubes. In a few minutes the ice cubes are small

Tcecarenko [31]

Answer:

Option A

Step-by-step explanation:

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3 0

3 years ago