2z2-9z+5
you have to do 23 -18 to get the 5 and since there is nothing else that u can factor at the moment u just need to right in the proper order which is 2z2-9z+5
F(-3) = 4(-3) - 3 = -12 - 3 = -15.
H(2) = -5(2) + 7 = -10 + 7 = -3.
F(-3) + H(2) = -15 + -3 = -18.
The solution is -18.
Answer:
11 players
Step-by-step explanation:
In a football tryouts at a local school there are 16 coaches and 44 players
Therefore spilliting then into group with similar numbers can be illustrated as follows
= 16/4
= 4 coaches each
= 44/4
= 11 players each
Hence sharing them into groups will result in 4 coaches and 11 players for each group
<h3>
Answer: an = 6n - 15 (Choice C)</h3>
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Explanation:
This sequence is arithmetic
The first term is a = -9
The common difference is d = 6 since we're adding 6 to each term to get the next one (eg: -3+6 = 3 or 3+6 = 9 or 9+6 = 15)
Plug those values into the arithmetic nth term formula below
an = a + d*(n-1)
an = -9 + 6*(n-1)
an = -9 + 6n-6
an = 6n - 15
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As a check, let's plug in something like n = 1
an = 6n - 15
a1 = 6*1 - 15
a1 = 6 - 15
a1 = -9
We see that the 1st term is -9, which matches the sequence given
Now let's plug in n = 2
an = 6n - 15
a2 = 6*2 - 15
a2 = 12 - 15
a2 = -3
The 2nd term is -3. This also matches.
I'll let you check the other values of n to confirm the answer.
