What is the perimeter 5 3/4 and 2 1/3

Mathematics

1 answer:

soldi70 [24.7K]3 years ago

6 0

16 2/12

I hope this helps :)

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A candy company claims that 20% of the candies in its bags are colored green. Steve buys 30 bags of 30 candies, randomly selects

Allisa [31]

Answer:

The probability of Steve agreeing with the company’s claim is 0.50502.

Step-by-step explanation:

Let X denote the number of green candies.

The probability of green candies is, p = 0.20.

Steve buys 30 bags of 30 candies, randomly selects one candy from each, and counts the number of green candies.

So, n = 30 candies are randomly selected.

All the candies are independent of each other.

The random variable X follows a binomial distribution with parameter n = 30 and p = 0.20.

It is provided that if there are 5, 6, or 7 green candies, Steve will conclude that the company’s claim is correct.

Compute the probability of 5, 6 and 7 green candies as follows:

$P(X=5)={30\choose 5}(0.20)^{5}(1-0.20)^{30-5}=0.17228\\\\P(X=6)={30\choose 6}(0.20)^{6}(1-0.20)^{30-6}=0.17946\\\\P(X=7)={30\choose 7}(0.20)^{7}(1-0.20)^{30-7}=0.15328$

Then the probability of Steve agreeing with the company’s claim is:

P (Accepting the claim) = P (X = 5) + P (X = 6) + P (X = 7)

= 0.17228 + 0.17946 + 0.15328

= 0.50502

Thus, the probability of Steve agreeing with the company’s claim is 0.50502.

7 0

3 years ago

The following data values represent a population. What is the variance of the values? 7, 5, 11, 1, 11

MaRussiya [10]

The mean is 35/5=7

The variance is the average of the sum of squared differences of each element from the mean:

v=((7-7)^2+(5-7)^2+(11-7)^2+(1-7)^2+(11-7)^2)/5

v=(0+4+16+36+16)/5

v=14.4

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3 years ago

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Add the two complex numbers 6 + 7i and 10 + 2i. Write your answer as a complex number in standard form, a + bi.

11111nata11111 [884]

6+ 7i

+10+2i

---------------------

16 +9i

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3 years ago

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