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2 years ago

The original price is $125. The sale price is $81.25. How much was the discount as a percent?

Mathematics

2 answers:

Annette [7]2 years ago

8 0

Answer:

Discount Percent = 35.00 %

Step-by-step explanation:

125-81.25=43.75 actual discount

43.75/125 = 0.35 actual discount / original

0.35 as percentage = 35%

Westkost [7]2 years ago

6 0

Answer: 35%

Step-by-step explanation:

Start by subtracting the original price by the sale price.

125-81.25=43.75

Now divide that amount by the original price.

$\frac{43.75}{125} =0.35$

Multiply that value by 100 for the answer

0.35×100=35

35%

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Answer:

She will use 5/6 pound for the entire garden

Step-by-step explanation:

Here, we want to know the total number of pounds that will be used for the full garden.

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3 years ago

Can someone help me

worty [1.4K]

Answer:

B = 129

Step-by-step explanation:

Opposite angles of a parallelogram are equal (or congruent)

A and C are both 51.

All angles in a parallelogram equal 360

Take both the known angles and substract from 360, than divide by 2.

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3 years ago

Which of the following is not a function

andrey2020 [161]

D is not a function

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3 years ago

Suppose that the times required for a cable company to fix cable problems in its customers’ homes are uniformly distributed betw

vampirchik [111]

Answer:

a) 60% probability that a randomly selected cable repair visit will take at least 50 minutes

b) 60% probability that a randomly selected cable repair visit will take at most 55 minutes.

c) The expected length of the repair visit is 52.5 minutes.

d) The standard deviation is 7.22 minutes.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X lower than x is given by the following formula.

$P(X \leq x) = \frac{x - a}{b-a}$

For this problem, we have that:

Uniformly distributed between 40 and 65 minutes, so $a = 40, b = 65$

(a) What is the probability that a randomly selected cable repair visit will take at least 50 minutes?

Either it takes less than 50 minutes, or it takes at least 50 minutes. The sum of the probabilities of these events is decimal 1. So

$P(X < 50) + P(X \geq 50) = 1$

The intervals can be open or closed, so

$P(X < 50) = P(X \leq 50)$

We have that

$P(X \geq 50) = 1 - P(X < 50)$

$P(X < x) = \frac{50 - 40}{65 - 40} = 0.4$

$P(X \geq 50) = 1 - P(X < 50) = 1 - 0.4 = 0.6$

60% probability that a randomly selected cable repair visit will take at least 50 minutes

(b) What is the probability that a randomly selected cable repair visit will take at most 55 minutes?

This is $P(X \leq 55)$

$P(X \leq 55) = \frac{55 - 40}{65 - 40} = 0.6$

60% probability that a randomly selected cable repair visit will take at most 55 minutes.

(c) What is the expected length of the repair visit?

The mean of the uniform distribution is:

$M = \frac{a+b}{2}$

$M = \frac{40+65}{2} = 52.5$

The expected length of the repair visit is 52.5 minutes.

(d) What is the standard deviation?

The standard deviation of the uniform distribution is

$S = \sqrt{\frac{(b-a)^{2}}{12}}$

$S = \sqrt{\frac{(65-40)^{2}}{12}}$

$S = 7.22$

The standard deviation is 7.22 minutes.

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maw [93]

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