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Lera25 [3.4K]
2 years ago
8

Last year, 351 children signed up to play football in Johnston County. Each single team had 27 players on its roster.

Mathematics
1 answer:
dedylja [7]2 years ago
7 0

Answer:

13 teams

Step-by-step explanation:

You have 351 children, and each team has 27 players.
Putting this into an equation you get:

351 ÷ 27 = x
x = 13

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How do you model the square root of 16
kotegsom [21]
\sqrt{16} =\sqrt{4*4}=\sqrt{4}*\sqrt{4}=2*2=4


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2 years ago
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It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute
hoa [83]

Answer:

Obese people

Lower = \mu - 2\sigma = 373- 2(67) = 239

Upper = \mu + 2\sigma = 373+ 2(67) = 507

Lean People

Lower = \mu - 2\sigma = 526- 2(107) = 312

Upper = \mu + 2\sigma = 526+ 2(107) = 740

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, "almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ)".

Solution to the problem

Obese people

Let X the random variable that represent the minutes of a population (obese people), and for this case we know the distribution for X is given by:

X \sim N(373,67)  

Where \mu=373 and \sigma=67

On this case we know that 95% of the data values are within two deviation from the mean using the 68-95-99.7 rule so then we can find the limits liek this:

Lower = \mu - 2\sigma = 373- 2(67) = 239

Upper = \mu + 2\sigma = 373+ 2(67) = 507

Lean People

Let X the random variable that represent the minutes of a population (lean people), and for this case we know the distribution for X is given by:

X \sim N(526,107)  

Where \mu=526 and \sigma=107

On this case we know that 95% of the data values are within two deviation from the mean using the 68-95-99.7 rule so then we can find the limits liek this:

Lower = \mu - 2\sigma = 526- 2(107) = 312

Upper = \mu + 2\sigma = 526+ 2(107) = 740

The interval for the lean people is significantly higher than the interval for the obese people.

5 0
2 years ago
Writing in Math Stacy multiplied 5 x 9 and said the nswer was 44. What two patterns could you use to show nat her answer is not
marusya05 [52]

Answer:

5*9= 45

Step-by-step explanation

Well using your hands you can put down your fifth finger and that will give you four fingers on the left and five on the right that then equals 45

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Is 5266 divisible by 2
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Answer:

yes it is, the answer is 2633

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Enter the equivalent distance in km in the box.
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60 000 cm = 600m                

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600m ÷ 1000 = 0.6km                        
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