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Ede4ka [16]
4 years ago
7

The 20-inch-diameter wheels of one car travel at a rate of 24 revolutions per minute,

Mathematics
1 answer:
nydimaria [60]4 years ago
8 0
One revolution of a wheel is equal to it's circumference:

C = πd

C: circumference
d: diameter

<u>20" wheel</u>
d = 20"
C = (20π) in/rev
v = (24 rev/min)(20π in/rev) = 480π in/min

<u>30" wheel</u>
d = 24"
C = (30π) in/rev
v = (18 rev/min)(30π in/rev) = 540π in/min

Ratio =  \frac{velocity of 30" wheel}{velocity of 20" wheel} =  \frac{v_{2}}{v_{1}}

\frac{v_{2}}{v_{1}} =  \frac{540\pi}{480\pi}  = \frac{9}{8}












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Alenkasestr [34]

The new volume is Nine time the original volume

Step-by-step explanation:

Let the length be 'l'

Let the height be 'h'

Let the width be 'w'

Volume of a rectangular prism= l x w x h

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New width = 2w

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New volume= (1.5l) x (2w) x (3h)

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The new volume is 9 time the original volume

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evablogger [386]

Answer:

D.) -4/5

Step-by-step explanation:

Ok, so we need to calculate the change in y over the channge in x, rise over run.

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2 years ago
Age of car = 8 years. Original cost = $18,000. The cost of maintenance and repairs is $
creativ13 [48]

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musickatia [10]

Answer:

\frac{2p-1}{3}

Step-by-step explanation:

Since you want to get q only and q appears in both side of the equation. Try to isolate q to one side.

1) Expand 2(q+p)

2q + 2p = 1 + 5q

2) Move all q terms to one side

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