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Bezzdna [24]
2 years ago
7

A jar contains nine black buttons and four brown buttons. If nine buttons are picked

Mathematics
1 answer:
allsm [11]2 years ago
7 0

Answer:

9/13

Step-by-step explanation:

Total = 9 + 4

= 13

Probability: 9/13

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Lana71 [14]

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the graph is continuous

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What does 4/5 % of 500 equal?
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4? since 500x8/1000 is 4
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Three men and eight women are waiting to be interviewed for jobs. If they are all selected in random​ order, find the probabilit
irakobra [83]

The probability that all men will be interviewed first is; 1/55

<h3>How to find probability combination?</h3>

To solve this question we will make use of the probability combination formula which is;

nCr = n!/(r! * (n - r)!)

Thus, since we want to find the probability that all men will be interviewed first, then we will use the formula;

3(3!)/((11C1) * (10C1) * (9C1)) = 18/990

Simplifying that fraction  gives us; 1/55

Read more about Probability Combination at; brainly.com/question/4658834

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7 0
2 years ago
Jim bought a meal in a town that has no sales tax. He tlps 15%. Select all the meals Jim could buy for less than or equal to $30
shusha [124]

Jim bought a meal in a town that has no sales tax. He tlps 15%. All the meals Jim could buy for less than or equal to $30 total are $20.54 meal and $26.08 meal.​

7 0
3 years ago
A​ bank's loan officer rates applicants for credit. The ratings are normally distributed with a mean of 200 and a standard devia
Butoxors [25]

Answer:

Probability that their mean is above 215 is 0.0287.

Step-by-step explanation:

We are given that a bank's loan officer rates applicants for credit. The ratings are normally distributed with a mean of 200 and a standard deviation of 50.

For this, 40 different applicants are randomly​ selected.

<em>Let X = ratings for credit</em>

So, X ~ N(\mu=200,\sigma^{2}=50^{2})

Now, the z score probability distribution for sample mean is given by;

         Z = \frac{X-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean = 200

           \sigma = standard deviation = 50

           \bar X = sample mean

           n = sample of applicants = 40

So, probability that their mean is above 215 is given by = P(\bar X > 215)

    P(\bar X > 215) = P( \frac{X-\mu}{\frac{\sigma}{\sqrt{n} } } > \frac{215-200}{\frac{50}{\sqrt{40} } } ) = P(Z > 1.897) = 1 - P(Z \leq 1.897)

                                                         = 1 - 0.97108 = 0.0287

Therefore, probability that their mean is above 215 is 0.0287.

5 0
3 years ago
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