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Dominik [7]
3 years ago
13

1. Rotate Ali the Alien 180°. Be sure to identify your center of rotation.

Mathematics
1 answer:
wariber [46]3 years ago
6 0

Complete Question

The complete question is shown on the first uploaded image

Answer:

The result of the rotation is Ali the Alien having the same orientation before the rotation.

The center of rotation is the same as the center of Ali the Alien.

Step-by-step explanation:

Let's take the center of Ali the Alien as the center of rotation, so when Ali the Alien is rotated through 180° we will discover that Ali the Alien will have the same orientation as he did before the rotation.

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KATRIN_1 [288]
1. 8
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those are the answers in order, hope this helps!
5 0
3 years ago
Jojo likes to paint She estimates the number of paintings she completes using the function P(W) = w – 2. where w is the number o
KATRIN_1 [288]

Answer:

P[J(y)] = 2/3 * J(y) -2

Step-by-step explanation:

4 0
3 years ago
Select the statement that correctly describes the expression below
Kitty [74]

Answer:

B

Step-by-step explanation:

The equation is (2x+5)^2.

It can't be A because 2 is the multiplier for only x.

It can't be C because the square is outside of the equation.

It can't be D because again, the square is outside of the equation.

So the only thing left is B.

Hope this helped!


7 0
3 years ago
Derive this with respect to x<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B%281%20%2B%20%20secx%29%20%7D%20" id="Tex
Elenna [48]

~~~~\dfrac{d}{dx} \left(\dfrac{3}{1 + \sec x} \right)\\\\\\=3 \dfrac{d}{dx} \left( \dfrac 1{ 1+ \sec x} \right)\\\\\\=3 \dfrac{d}{dx} (1+ \sec x)^{-1}\\\\\\=3 (-1) (1 + \sec x )^{-1 -1} \dfrac{d}{dx}( 1 + \sec x)\\\\\\=-3(1 + \sec x)^{-2}  ( 0 + \sec x  \tan x)\\\\\\=-\dfrac{3\sec x \tan x}{(1 + \sec x)^2}

8 0
2 years ago
BRAINLIESTTT ASAP! PLEASE HELP ME :)
GrogVix [38]

Answer:

<u>1. Type of function</u>: absolute value function

<u>2. The three transformations from the parent function f(x) = |x| are</u>:

  • Translation 3 units to the left
  • Vertical stretch with a scale factor of 2
  • Translation 5 units downward

Explanation:

<u>1. Type of function</u>

The parent function |x| is the absolute value function. It returns the positive value of the argument (x).

Thus the function f(x) = 2|x + 3| - 5 is also an absolute value function.

It returns the positive value of x + 3, then multiplyes it by 2, and finally subtract 5.

This is a piecewise function.

For the values of x ≥ - 3, the output is 2(x +3) - 5 = 2x + 6 - 5 = 2x + 1.

For the values of x < - 3, the output is 2 (-x - 3) - 5 = -2x - 6 - 5 = -2x - 11.

The vertex of this function is at x = - 3: 2 (- 3 + 3) - 5 = 2(0) - 5 = 0 - 5 = 5.

Thus the vertex is (-3, 5).

<u>2. Transformations from the parent function f(x) = |x|</u>.

When you know the parent function and the daughter function you can know the transformations done of the former to get the later by some simple rules.

a)<u> Translation in the horizontal direction</u>.

When you add a positive value to the argument the function is translated to the left.

Thus, when you add 3 to x, |x| becomes |x + 3| and it is a translation 3 units to the left.

b) <u>Vertical stretch</u>

When you multiply the argument by a constant, the function stretches vertically.

Thus, when you multiply |x + 3| by 2, to get 2|x + 3|, the function is vertically stretched by a scale factor of 2.

c) <u>Vertical translation</u>

When you subtract a constant value from the function, you translate it downward.

Thus, when you subtract 5 from 2|x + 3| - 5, you translate the function 5 units downward.

6 0
3 years ago
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