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Art [367]
2 years ago
9

What is the area of base for 7mm height and 7mm radius cylinder?​

Mathematics
1 answer:
sveta [45]2 years ago
3 0

Answer:

153.94 mm^2

Step-by-step explanation:

area of base = area of a circle = Pi * radius squared

radius squared = 49

area of base =  Pi * 49

area of base =  153.94

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Graph a line that contains the point -6,1 and has a slope of 5
Stells [14]

Answer:

y=5x+31

Step-by-step explanation:

y=mx+b

1=(-6*5)+b

1=-30+b

31=b

y=5x+31

(5*-6)+31

-30+31

1

you can also graph a line on desmos

7 0
3 years ago
Read 2 more answers
If the endpoints of the diameter of a circle are (10, 12) and (0, 2), what is the standard form equation of the circle? A) (x +
attashe74 [19]
So the equation of a circle is (x - h)² + (y - k)² = r² where (h,k) are the coordinates of the center of the circle and r is the radius. The diameter of a circle is a line that goes from one point of the circle to the other through the center of the circle. Well the center would be midway through the diameter so use midpoint formula to find the center which is (h,k) Mid point formula is both given x's added together divided by 2 for h and both y coordinates added together divided by 2 to find k
(10+0)/2
10/2= 5
(12+2)/2
14/2 = 7
so the center of the circle is (5,7) now use distance formula using the center and one of the points to the radius
√((5-10)²+(7-12)²)
√(-5²+ -5²)
√(25 + 25)
√50 is the radius
Now plug all found information into circle equation
(x-5)² + (y-7)² =50      note the end is 50 because the circle equation is radius squared and since the radius is √50, radius² is 50.
Answer is c
8 0
3 years ago
Read 2 more answers
the slope of a line passing through h (-2, 5) is -3/4. Which ordered pair represents a point on this line? ​
rosijanka [135]

Answer:

A

Step-by-step explanation:

Calculate the slope of the given points with the point (- 2,  5 )

If the slope is - \frac{3}{4} then the point is on the line

Calculate slope m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (- 2, 5) and (x₂, y₂ ) = (6, - 1)

m = \frac{-1-5}{6+2} = \frac{-6}{8} = - \frac{3}{4} ← point (6, - 1) is on the line

Repeat with (x₁, y₁ ) = (- 2, 5 ) and (x₂, y₂ ) = (2, 8)

m = \frac{8-5}{2+2} = \frac{3}{4} ← point (2, 8) is not on the line

Repeat with (x₁, y₁ ) = (- 2, 5) and (x₂, y₂ ) = (- 5, 1)

m = \frac{1-5}{-5+2} = \frac{-4}{-3} = \frac{4}{3} ← point (- 5, 1) is not on the line

Repeat with (x₁, y₁ ) = (- 2, 5) and (x₂, y₂ ) = (1, 1)

m = \frac{1-5}{1+2} = - \frac{4}{3} ← point (1, 1) is not on the line

Thus the point on the line is (6, - 1 ) → A

4 0
3 years ago
17. Evaluate a. 6! b. 8P5 c. 12C4
Andreyy89
The factorial ! just means we multiply by every natural number less that the value so
6! =6×5×4×3×2×1= 720

for permutations we use the formula n!/(n-r)!
so we have 8!/(8-5)!=8!/3!=8×7×6×5×4

for combinations s we have n!/(n-r)!r!
so we have 12!/(12-4)!4!=12!/8!4!=12×11×10×9/4×3×2=11×10×9/2=99×5
7 0
3 years ago
What is the trigonometric derivative of Y=2sinx-tanx
Alchen [17]
\bf y=2sin(x)-tan(x)\implies \cfrac{dy}{dx}=2cos(x)-sec^2(x)
7 0
3 years ago
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