1+1 then divide by 8

Find three consecutive even integers such that the sum of the first, twice the second, three times the third is -76. What is the

ss7ja [257]

Answer:

The numbers are -14,-13 and -12

Step-by-step explanation:

The correct question is

Find three consecutive integers such that the sum of the first, twice the second and three times the third is -76. What is the number?

Let

x ----> the first consecutive integer

x+1 ---> the second consecutive integer

x+2 ---> the third consecutive integer

we have that

$x+2(x+1)+3(x+2)=-76$

solve for x

apply distributive property

$x+2x+2+3x+6=-76$

Combine like terms

$6x+8=-76$

subtract 8 both sides

$6x=-76-8$

$6x=-84$

Divide by 6 both sides

$x=-14$

so

$x+1=-14+1=-13$

$x+2=-14+2=-12$

therefore

The numbers are -14,-13 and -12

3 0

3 years ago

Rewrite the equation 4x + 5x2 = 8x – 7 in standard form and

Makovka662 [10]

Answer:

The correct option is a=5, b = -4, c=7 ....

Step-by-step explanation:

The standard form is ax²+bx+c=0

where a, b, and c being constants, or numerical coefficients, and x is an unknown variable.

The given expression is:

4x + 5x2 = 8x – 7

To make it a standard equation we will move all the values to the left hand side and 0 will be left at the right hand side.

4x+5x²-8x+7=0

Now solve the like terms and arrange the equation according to the standard form:

ax²+bx+c=0

5x² - 4x +7 =0

Here a = 5

b = -4

c= 7

Thus the correct option is a=5, b = -4, c=7 ....

4 0

3 years ago

What is the answer to Factor 3a^2-6a

Anton [14]

Hi there!

$3 {a}^{2} - 6a \: = 3a(a - 2)$

We can see this by writing the factors as multipliers. We get the following:
$3a {}^{2} = 3 \times \: a \times a$
$6a = 3 \times 2 \times a$

Now we can see that the terms that are in common are 3 and a, and therefore we can bring those outside the parenthesis.

7 0

3 years ago

Find the domain and range of f(x) = 2 square root of x-2

Neporo4naja [7]

$f(x)=2\sqrt{x-2}\\\\The\ domain:\\x-2\geq0\to x\geq2\\\boxed{x\in[2;\ \infty)}\\\\The\ range:\\\boxed{y\in[0;\ \infty)}$

$If\ f(x)=2\sqrt{x}-2,\ then\\\\The\ domain:\boxed{x\in[0;\ \infty)}\\\\The\ range:\boxed{y\in[-2;\ \infty)}$

5 0

3 years ago

HELP NOW!!!!

VMariaS [17]

Using the concept of probability and the arrangements formula, there is a

0.002 = 0.2% probability that the first 8 people in line are teachers.

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A probability is the number of desired outcomes divided by the number of total outcomes.
The order in which they are positioned is important, and all people will be positioned, and thus, the arrangements formula is used to find the number of outcomes.

The number of possible arrangements from a set of n elements is given by:

$A_n = n!$