Answer:
She has to read 2/6 more by the end of her vacation if she wants to finish 3/6 (1/2) of the book.
Step-by-step explanation:
If this wasn't the answer you were looking for please tell me so I can redo it.
<h3>
Answer: x = 6</h3>
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Work Shown:
Those are the possible solutions, but plugging x = -14 back into the original equation will lead to an error. So we rule x = -14 out
x = 6 works as a solution however
Your sum is 4 times 10, or 40. We want to end up with 40. Subtract 8 because you added 8 before to work backwards. You get 32. Divide by 16 because the opposite of multiplication is division. You would get 2.
<span>2≤x≤8</span>
<span>−4≤<span>f′</span>(x)≤5</span>
f is continuous in differentable on [2,8] so we know there is c btw 2 and 8 such that
<span><span>f′</span>(c)=<span><span>f(8)−f(2)</span><span>/8−2</span></span></span>
And we know
<span>−4≤<span>f′</span>(c)≤5</span>
=> we have
<span>−4≤ <span><span>f(8)−f(2)</span><span>/8−2</span></span> ≤<span>5</span></span>
