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pashok25 [27]
3 years ago
12

Two of the opposite vertices of a square have the coordinates (4, - 4) and ( - 3, 3) respectively as shown on the grid below. Wh

ich of the following are the coordinates of the OTHER two vertices of the square?
Mathematics
1 answer:
iogann1982 [59]3 years ago
6 0

Answer:

(4 , 3 ) and (-3 , -4)

Step-by-step explanation:

Other two vertices will be in 1st quadrant and 3 rd quadrant

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What is the result when the number 16 is decreased by 25%?
forsale [732]

Answer: 4

Step-by-step explanation: 25% is 1/4 of 100. You can divide 16/4 to find your answer which is 4. This method may not work all the time, but it is a simple way I like to use.

By the way, can I please be marked brainliest? I need them to rank up :(

3 0
3 years ago
Help me please please
Viefleur [7K]
1. a=3
2. c=8.9
3. c=6.3
4. c=26
5. c=7.8
6. c=17
7. c=10
8. b=15
9. b=10.7
10. a=13.2
11. yes
12. no
13. yes
14. no
15. yes
16. no
4 0
3 years ago
Read 2 more answers
Help pls anyone!!! plsss
murzikaleks [220]

Answer:

1.) 22+(33+44)

2.) (5+3)+(1+9)

3.) (-a+d)+(-c+b)

Step-by-step explanation:

Associative property of addition: Changing the grouping of addends does not change the sum. For example,

(2+3)+4= 2+(3+4)

No matter how you rearrange the numbers, they will always add to the same amount.

3 0
3 years ago
Read 2 more answers
Team D's car went the same distance on each of its trials. Team C's car went exactly 1 cm farther in each trial than Team D's ca
mezya [45]

Answer:

180 cm

Step-by-step explanation:

Number of trials per team = 3

Distance per trial for team D's car is the same for each trial, let distance = x

Distance per trial for team C's car is 1cm farther than team D's distance and the same for each trial, hence, distance = x + 1 per trial

Total distance traveled by C = 543 cm

This means :

(x + 1) + (x + 1) + (x + 1) = 543

3x + 3 = 543

3x = 543 - 3

3x = 540

x = 540 / 3

x = 180

Hence, distance traveled per trial for team D's car = x = 180 cm

8 0
3 years ago
Find the discriminant of x2-6x -10 = 0, and determine the number of real solutions of the equation.​
sergiy2304 [10]

Answer:

76

2 real solutions

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

Standard Form: ax² + bx + c = 0

Discriminant: b² - 4ac

  • Positive - 2 solutions
  • Equal to 0 - 1 solution
  • Negative - No solutions/Imaginary

Step-by-step explanation:

<u>Step 1: Define</u>

x² - 6x - 10 = 0

<u>Step 2: Identify Variables</u>

<em>Compare quadratic.</em>

x² - 6x - 10 = 0 ↔ ax² + bx + c = 0

a = 1, b = -6, c = -10

<u>Step 3: Find Discriminant</u>

  1. Substitute in variables [Discriminant]:                                                            (-6)² - 4(1)(-10)
  2. [Discriminant] Evaluate exponents:                                                                36 - 4(1)(-10)
  3. [Discriminant] Multiply:                                                                                    36 + 40
  4. [Discriminant] Add:                                                                                          76

This tells us that our quadratic has 2 real solutions.

8 0
3 years ago
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