Question

What is the equation of the line that passes through the point (-2,2) and the point (-6,4)?

Answer 1

Answer:

y = -1/2x+1

Step-by-step explanation:

First step is to find the slope

m = (y2-y1)/(x2-x1)

    = ( 4-2)/(-6 - -2)

       (4-2)/(-6+2)

       2/-4

     -1/2

Then we can use the slope intercept form of a line

y = mx+b  where m is the slope and b is the y intercept

y = -1/2x+b

Substitute a point into the equation to find b

2 = -1/2(-2) +b

2 = 1+b

Subtract 1 from each side

1 =b

y = -1/2x+1

Answer 2

y = mx + b

Where m = slope and b is the y intercept

Let's find the slope = change in y/change in x

m = (4-2)/(-6+2) = 2/-4 = -1/2

Now we have:

y = (-1/2)x + b

Now substitute point (-6,4)

4 = (-1/2)(-6) + b

4 = 3 + b

b = 1

So y = (-1/2)x + 1 is the equation

ANSWER:

$y=(-\frac{1}{2})x$+1

so letter c