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3 years ago

Which descriptions from the list below accurately describes the relationship between both

Mathematics

1 answer:

larisa [96]3 years ago

7 0

Similar, they have the same angles but different sides.
Congruent is same sides, same angles.
The other 2 just ignore.

The answer is similar.

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Lines a and b are parallel Line cis perpendicular to both line a and line b. Which

prohojiy [21]

Answer:

see below

Step-by-step explanation:

The slopes of parallel lines are the same. The slopes of perpendicular lines are negative reciprocals of each other, hence their product is -1.

___

For the most part, the concept of adding slopes of lines does not relate to parallel or perpendicular lines in any way.

6 0

3 years ago

Read 2 more answers

For which independent value do the equations generate the same dependent value? y1=6x-16 , y2=3x-10

Nikitich [7]

The question asks which x-value gives the same y-value for both equations, so if you need the ys to be equal, you can set both equations equal to each other, giving you 6x-16=3x-10. Now, solve for x. 6x-16=3x-10, subtract 3x and add 16, 3x=6, divide 3, x=2. Your answer is x=2.

7 0

3 years ago

X= 2 and y = 4, then -X-XY

Fed [463]

Answer:

-10

Step-by-step explanation:

= -X - XY

= -2 - 2×4

= -2 - 8

= -10

therefore, -X - XY = -10

5 0

3 years ago

Read 2 more answers

Help me with this problem please i’m confused

Taya2010 [7]

Answer:

3rd

Step-by-step explanation:

If you know about linear eq. it's just a simple rule no worry

3 0

2 years ago

The following statement is either true (in all cases) or false (for at least one example). If false, construct a specific e

matrenka [14]

Answer:

False, counterexample below

Step-by-step explanation:

Denote the unit vectors of R^3 by $e_1=(1,0,0), e_2=(0,1,0), e_3=(0,0,1)$ . Now consider $v_1=e_1, v_2=2e_1$ and $v_3=e_3$ . We have that $v_1, v_2,v_3 \in \mathbb{R}^3$ . Also, the vector $v_3$ is not a linear combination of $v_1, v_2$ because any linear combination of these two vectors will have third coordinate zero, but v_3 has third coordinate 1 so they can't be equal.

However, the set $\{v_1, v_2,v_3\}$ is not linearly independent, because $2v_1-v_2+0v_3=0$ is a non-trivial linear combination of these vectors that equals zero.

4 0

4 years ago