Awnser:
I just need points
Step by step;
Answer:
No solution or x ∈ ∅
Step-by-step explanation:
We have given the equation ⇒ x+12 = (x+14) -3
if we solve this equation ⇒ x+12 = x+14-3
⇒x+12= x+11
⇒12 ≠ 11
which state that x ∈ ∅
i.e. there is no value of x which make the equation true
therefore, No solution
Answer:
d
Step-by-step explanation:
If that point lies on the graph of y, then one side will equal each other.
Let x = 3 and y = -5
-5 = -2(3) + 1
-5 = -6 + 1
-5 = -5
The left side = the right side.
So, the given point lies on the given line.
Answer:
The probability that the average final exam grade of this sample is between 77 and 82
P(77≤ x⁻≤ 82 = 0.8315 or 83%
Step-by-step explanation:
<u><em>Step(i):</em></u>-
Given random sample size 'n' = 40
Mean of the normal distribution = 81
Standard deviation of normal distribution = 6.6
Let x₁⁻ = 77
![Z_{1} = \frac{x_{1} -mean }{\frac{S.D}{\sqrt{n} } } = \frac{77-81}{\frac{6.6}{\sqrt{40} } }](https://tex.z-dn.net/?f=Z_%7B1%7D%20%3D%20%5Cfrac%7Bx_%7B1%7D%20-mean%20%7D%7B%5Cfrac%7BS.D%7D%7B%5Csqrt%7Bn%7D%20%7D%20%7D%20%3D%20%5Cfrac%7B77-81%7D%7B%5Cfrac%7B6.6%7D%7B%5Csqrt%7B40%7D%20%7D%20%7D)
Z₁ = -3.83
Let x₂⁻ = 77
![Z_{2} = \frac{x^{-} _{2} -mean }{\frac{S.D}{\sqrt{n} } } = \frac{82-81}{\frac{6.6}{\sqrt{40} } }](https://tex.z-dn.net/?f=Z_%7B2%7D%20%3D%20%5Cfrac%7Bx%5E%7B-%7D%20_%7B2%7D%20-mean%20%7D%7B%5Cfrac%7BS.D%7D%7B%5Csqrt%7Bn%7D%20%7D%20%7D%20%3D%20%5Cfrac%7B82-81%7D%7B%5Cfrac%7B6.6%7D%7B%5Csqrt%7B40%7D%20%7D%20%7D)
Z₂ = 0.958
<em>The probability that the average final exam grade of this sample is between 77 and 82</em>
P(77≤ x≤ 82) = P( -3.83 ≤x≤0.958)
= A( 0.958) + A(3.83)
= 0.3315 + 0.4995
= 0.8315
<em>The probability that the average final exam grade of this sample is between 77 and 82 = 0.8315 or 83%</em>