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Anna [14]
2 years ago
9

There is a pair of parallel sides in the following shape. What is the area of the shape?

Mathematics
1 answer:
Mama L [17]2 years ago
3 0

Answer:

The given shape is Trapezium

Area of Trapezium= 1/2h(L1+L2)

=1/2×7×(11+3

=1/2×7×14

=49

Your answer is 49

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3 years ago
Use Newton's method with initial approximation x1 = −2 to find x2, the second approximation to the root of the equation x3 + x +
nevsk [136]

Answer:

x_2 \approx -1.769

Step-by-step explanation:

Let f(x)=x^3+x+7

So f'(x)=3x^2+1

x_{n+1}=x_n-\frac{f(x_n)}{f'(x_n)}

Let x_1=-2

We are going to find x_2

So we are evaluating -2-\frac{f(-2)}{f'(-2)}

First step find f(-2)

Second step find f'(-2)

Third step plug in those values and apply PEMDAS!

f(-2)=(-2)^3+(-2)+7=-8-2+7=-10+7=-3

f'(-2)=3(-2)^2+1=3(4)+1=12+1=13

So

x_2=-2-\frac{-3}{13} \\\\ x_2=\frac{-26+3}{13} \\\\ x_2=\frac{-23}{13} \\\\ x_2 \approx -1.769

5 0
3 years ago
I need help please help
Bogdan [553]
D.

you cannot have a negative amount of rainfall, so the predicted value of -32.4cm doesn't make sense.
8 0
3 years ago
Evaluate exactly the value of the integral from -1 to 0 (2x^4+8x)^3 (4x^3+4),dx. Include the use of substitution and the antider
ddd [48]
Hello,

Let's be

 z=2x^4+8x \\
dz=(8x^3+8)\ dx=8(x^3+1)\ dx \\

 \int\limits^0_{-1} {(2x^4+8x)^3*(4x^3+4)} \, dx =4* \int\limits^0_{-6} { \dfrac{z^3}{2}} \, dz \\
= 2* \left[\begin{array}{ccc} \dfrac{z^4}{4}\end{array}\right] ^0_{-6}=
\left[\begin{array}{ccc} \dfrac{z^4}{2}\end{array}\right] ^0_{-6}=0-648=-648

3 0
4 years ago
Help me answer this q1
Ostrovityanka [42]

Answer: B is the answer yup B

6 0
3 years ago
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