Answer:
Step-by-step explanation:
We want to create a third degree polynomial function with one zero at three.
In other words, we want to find a polynomial function with roots x=3 , multiplicity, 3.
Since x=3 is a solution, x-3 is the only factor that repeats thrice.
We expand to get:
This simplifies to:
See attachment for graph.
Answer:
sin^2 A
Step-by-step explanation:
first expand the trigonometry
1(1-cosA)+cosA(1-cosA)
=1-cosA+cosA-cos^2 A
= 1-cos^2 A
from trigonometric identity sin^2 A + cos^2 A= 1
sin^2 A= 1- cos^2 A
=sin^2 A
Step-by-step explanation:
30. i already know this sa. . ....
Answer:
Step-by-step explanation:
If you would like me to explain let me know in the comments.
Answer:
(-4, -2)
Step-by-step explanation:
A = (-1, 2)
Add (-3, -4) to that and you get ...
A' = (-1-3, 2-4) = (-4, -2) . . . . matches the last choice
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The translation function has the effect of moving the point left 3 and down 4. You can count grid squares on the graph to see that A' ends up at (-4, -2).
