the first two random numbers are 4,5.using linear congruential generator with a=4, m=11 and b=0 and 23 as the seed
linear congruential generator
Xn= an-+b Lm
0d s = 25 , b=6, YM 11, 024
Q O o m) 4, Lu) = 4x2%U)
m= 4x4j = 5 y-5
the numbers are 4, 5.
4.O0000 5.000TO
A linear congruence generator is an algorithm that returns a sequence of pseudorandom numbers computed using discontinuous piecewise linear equations. This method is one of the oldest and best-known pseudorandom number generator algorithms.
The linear congruential generator (LCG) is a pseudorandom number generator (PRNG ) is a class of algorithms. Random number generation plays an important role in many applications, from cryptography to Monte Carlo methods.
Learn more about linear congruential here: brainly.com/question/3168048
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Answer:
h(-5) = 129
Step-by-step explanation:
Put -5 where x is and do the arithmetic.
h(-5) = 4(-5)² -5(-5) +4
h(-5) = 4(25) +25 +4 = 129
Answer: 208.
Step-by-step explanation:
The formula to find the minimum sample size is given by :-
(1)
, where z* = critical z-value (two tailed).
= Standard deviation ( from prior study ) and E = Margin of error.
As per given , we have
Margin of error : E= 0.29
Confidence level = 85%
Significance level =
Using z-table , the critical value (two -tailed)=
As per previous study , Variance =
Now, the required minimum sample size = 
[Substitute the values in formula (1)]
[ Round to the next integer]
Hence, the minimum number of third graders that must be included in a sample = 208.
Answer:
160 meters
Step-by-step explanation:
Let call dj distance run by Jess and dw distance run by Wes
By Jess courtesy Wes will be 60 meters ahead of Jess
Let call t the time in which both runners are at the same point, which in fact is when both distances are equal
dj = 8 m/sec * t and dw = 60 + 5 m/sec * t
Then we make dj = dw
8*t = 60 + 5*t
3*t = 60
t = 20 sec
Now passed 20 sec dj = 8 * 20 = 160 m
and dw = 60 + 5*20 dw = 160 m
The second answer I believe. Sorry if I am wrong.
