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Lubov Fominskaja [6]

3 years ago

15

Jonna is 4 years older than her brother which of the following expression shows the sum of their ages if B represents Jonas brot

hers age

2 answers:

arlik [135]3 years ago

6 0

It is 4+B because it's Jonna's age plus her brother's age

Svet_ta [14]3 years ago

4 0

If B is Jonas and his sister is 4 years older, that would be 4 plus B

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Please explain how you got your answers! (: Solve the problem by using the counting principle.

Natasha2012 [34]

A. The number of fabric-pattern-color combinations is 4 * 13 * 9 = 468

B. P(1st choice) = no of novels / total books = 3/6 = 1/2
    P(2nd choice) = no of remaining novels/ total remaining books = 2/5
    P(both novels) = 1/2 * 2/5 = 1/5 (without replacement assumed)

C. P(1st choice) = no of biographies / total books = 2/6 = 1/3
    P(2nd choice) = no of remaining biographies/ total remaining books = 1/5
    P(both biographies) = 1/3 * 1/5 = 1/15 (without replacement assumed)

D. P(1st choice) = no of history books / total books = 1/6
    P(2nd choice) = no of novels/ total remaining books = 3/5
    P(a history, then a novel) = 1/6 * 3/5 = 1/10 (without replacement assumed)

7 0

3 years ago

Enrico is filling his pool. The pool has 3,000 gallons of water now. The water hose used by Enrico puts 500 gallons per hour in

Tju [1.3M]

Answer:

6

Step-by-step explanation:

5 0

4 years ago

Please help me with these questions. Thank you.

Bas_tet [7]

Answer:

36 x⁸y⁶

√2/2

Step-by-step explanation:

Factor 1296 into its prime factors

1296 = 24 • 34

To simplify a square root, we extract factors which are squares, i.e., factors that are raised to an even exponent.

Factors which will be extracted are :

1296 = 24 • 34

No factors remain inside the root !!

To complete this part of the simplification we take the squre root of the factors which are to be extracted. We do this by dividing their exponents by 2 :

36 = 22 • 32

At the end of this step the partly simplified SQRT looks like this:

36 √(x¹⁶y¹²)

STEP2:Simplify the Variable part of the SQRT

Rules for simplifing variables which may be raised to a power:

(1) variables with no exponent stay inside the radical

(2) variables raised to power 1 or (-1) stay inside the radical

(3) variables raised to an even exponent: Half the exponent taken out, nothing remains inside the radical. examples:

√(x⁸)=x⁴

√(x^-6)=x^-3

Applying these rules to our case we find out that

SQRT(x¹⁶y¹²) = x⁸y⁶

Combine both simplifications

sqrt (1296x¹⁶y¹²) = 36 x⁸y⁶

Simplified Root : 36 x⁸y⁶

number 2)

3√2/3√4=

=3√2/3×2

=3√2/6

=3√2/6 ×3/3

=1√2/2

=√2/2

3 0

2 years ago

An Amazon employee packed two boxes of identical books and calculators for shipping. One box held 3 books and 4 calculators. The

Afina-wow [57]

Answer:

pls make it clear

Step-by-step explanation:

6 0

3 years ago

If a random sample of size nequals=6 is taken from a population, what is required in order to say that the sampling distributio

goldenfox [79]

Answer:

$\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})$

In order to satisfy this distribution we need that each observation on this case comes from a normal distribution, because since the sample size is not large enough we can't apply the central limit theorem.

Step-by-step explanation:

For this case we have that the sample size is n =6

The sample man is defined as :

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

And we want a normal distribution for the sample mean

$\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})$

In order to satisfy this distribution we need that each observation on this case comes from a normal distribution, because since the sample size is not large enough we can't apply the central limit theorem.

So for this case we need to satisfy the following condition:

$X_i \sim N(\mu , \sigma), i=1,2,...,n$

Because if we find the parameters we got:

$E(\bar X) =\frac{1}{n} \sum_{i=1}^n E(X_i) = \frac{n\mu}{n}=\mu$

$Var(\bar X)= \frac{1}{n^2} \sum_{i=1}^n Var(X_i) = \frac{n\sigma^2}{n^2}= \frac{\sigma^2}{n}$

And the deviation would be:

$Sd (\bar X) = \frac{\sigma}{\sqrt{n}}$

And we satisfy the condition:

$\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})$

3 0

3 years ago