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levacccp [35]
3 years ago
9

D is the midpoint of AC. If AD = 2x + 6 and DC = 4x-7, what is the length of DC?

Mathematics
1 answer:
DENIUS [597]3 years ago
4 0
A----------D----------C

AD = 2x + 6
DC = 4x - 7

the midpoint D splits AC into 2 equal parts....therefore, AD = DC

2x + 6 = 4x - 7
2x - 4x = -7 - 6
-2x = - 13
x = -13/-2
x = 6.5 

DC = 4x - 7......4(6.5) - 7 = 19 <===
AD = 2x + 6.....2(6.5) + 6 = 19
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Answer:

The complete solution is

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Step-by-step explanation:

Given differential equation is

3y"- 8y' - 3y =4

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y = e^{mx}

Differentiating with respect to x

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Putting the value of y, y' and y'' in left side of the differential equation

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3m^2-8m-3=0

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The complementary function is

y= Ae^{3x}+Be^{-\frac13 x}

y''= D², y' = D

The given differential equation is

(3D²-8D-3D)y =4

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Since the linear operation is

L(D) ≡ (3D+1)(D-3)    

For particular integral

y_p=\frac 1{(3D+1)(D-3)} .4

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   =4\frac{1}{(3.0+1)(0-3)}      [ replace D by 0 , since L(0)≠0]

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The complete solution is

y= C.F+P.I

\therefore y= Ae^{3x}+Be^{-\frac13 x}-\frac43

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Answer:

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Step-by-step explanation:

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I graphed the inequality on the graph below.

If this answer is correct, please make me Brainliest!

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Dmitriy789 [7]

Answer:

2,3,5,then the last one

Step-by-step explanation:

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