Answer:
13 units
Step-by-step explanation:
So the length of those 2 points is 6+6 = 12.
The height would be 8-3 =5
Using pythagoras, you can find out the length of the line joining the 2 points so:
units
<h3>Given</h3>
trapezoid PSTK with ∠P=90°, KS = 13, KP = 12, ST = 8
<h3>Find</h3>
the area of PSTK
<h3>Solution</h3>
It helps to draw a diagram.
∆ KPS is a right triangle with hypotenuse 13 and leg 12. Then the other leg (PS) is given by the Pythagorean theorem as
... KS² = PS² + KP²
... 13² = PS² + 12²
... PS = √(169 -144) = 5
This is the height of the trapezoid, which has bases 12 and 8. Then the area of the trapezoid is
... A = (1/2)(b1 +b2)h
... A = (1/2)(12 +8)·5
... A = 50
The area of trapezoid PSTK is 50 square units.
Step-by-step explanation:
Use formula to find the slope/gradient
(-5, -1) = (x1, y1)
(5, 11) = (x2, y2)
So,
8x - 5(x - 3) = 18
8x - 5x + 15 = 18
3x = 18 - 15
3x = 3
x = 3/3
x = 1
Option C.
Given:
The graph of a rectangle.
The given rectangle is dilated from the origin by a scale factor of 3.
To find:
The vertices of the image of the rectangle after the dilation.
Solution:
From the given graph it is clear that the vertices of the rectangle are A(0,2), B(0,4), C(3,4) and D(3,2).
If a figure is dilated from the origin by a scale factor of 3, then
Using this rule, the vertices of the image are:
Similarly,
And,
And,
The vertices of the image after dilation are (0,6), (0,12), (9,12), (9,6).
Therefore, the correct options are B and F.