1. For x<3, h(x)=x+2
now x+2 is an increasing line (a practical way to check, h(1)=3, h(2)=4)
the largest value it takes is at 3, not inclusive, so h(3)=5 not inclusive.
Range_1= (-∞, 5)
2. for x> or equal to 3, h(x)=-x+8, which is a decreasing line (check h(4)=4, h(5)=3 )
so this line takes its maximal value at x=3, f(3)=5 and then takes any other value to -∞.
Range_2=(-∞,5]
3. Range(h)=Range1∪Range2=(-∞, 5)∪(-∞,5]=(-∞,5] (B)
Answer:
g(f(x)) = √(x^2 +17)
Step-by-step explanation:
For ...
f(x) = x^2 +9
g(x) = √(x +8)
The definition of g(f(x)) is ...
g(f(x)) = g(x^2 +9) = √((x^2 +9) +8)
g(f(x)) = √(x^2 +17)
Answer:
Step-by-step explanation:
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There is no solution because x is incorrect.
x should be 32
Answer:
No real solutions
Step-by-step explanation:
Divide both sides by 3
3x^3/3=-54/3
x^2=-18
Take square root
x=±√−18
