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rosijanka [135]
3 years ago
9

Corey has 140 marbles. He gives 16 to his younger brother. He divides the rest equally into four bags. How many go in each bag?

Mathematics
1 answer:
madreJ [45]3 years ago
8 0
31 marbles would go into each bag.
You might be interested in
In a right triangle, what is the 3rd angle measure if an angle is 25
melomori [17]

Answer:

65

Step-by-step explanation:

The sum of the angles in a triangle is 180. In a right triangle, there is one 90 degree angle. If the second angle is 25, and 90+25+the last angle must add up to 180, simple math can find the value of the last angle.

180-90-25=65

5 0
3 years ago
Read 2 more answers
If the heights of 300 students are normally distributed with mean 68.0 inches and standard deviation 3.0 inches, how many studen
Lunna [17]
Given:
μ = 68 in, population mean
σ = 3 in, population standard deviation

Calculate z-scores for the following random variable and determine their probabilities from standard tables.

x = 72 in:
z = (x-μ)/σ = (72-68)/3 = 1.333
P(x) = 0.9088

x = 64 in:
z = (64 -38)/3 = -1.333
P(x) = 0.0912

x = 65 in
z = (65 - 68)/3 = -1
P(x) = 0.1587

x = 71:
z = (71-68)/3 = 1
P(x) = 0.8413

Part (a)
For x > 72 in, obtain
300 - 300*0.9088 = 27.36

Answer: 27

Part (b)
For x ≤ 64 in, obtain
300*0.0912 = 27.36

Answer: 27

Part (c)
For 65 ≤ x ≤ 71, obtain
300*(0.8413 - 0.1587) = 204.78

Answer: 204

Part (d)
For x = 68 in, obtain
z = 0
P(x) = 0.5
The number of students is
300*0.5 = 150

Answer: 150

3 0
3 years ago
SOMEONE PLEASE ANSWER THIS CORRECTLY PLEASEEE
GrogVix [38]
You just multiply the numbers and if it’s less than that number you it it in the bud hood this helps!
7 0
2 years ago
Read 2 more answers
A solution initially contains 200 bacteria. 1. Assuming the number y increases at a rate proportional to the number present, wri
GuDViN [60]

Answer:

1.\frac{dy}{dt}=ky

2.543.6

Step-by-step explanation:

We are given that

y(0)=200

Let y be the number of bacteria at any time

\frac{dy}{dt}=Number of bacteria per unit time

\frac{dy}{dt}\proportional y

\frac{dy}{dt}=ky

Where k=Proportionality constant

2.\frac{dy}{y}=kdt,y'(0)=100

Integrating on both sides then, we get

lny=kt+C

We have y(0)=200

Substitute the values then , we get

ln 200=k(0)+C

C=ln 200

Substitute the value of C then we get

ln y=kt+ln 200

ln y-ln200=kt

ln\frac{y}{200}=kt

\frac{y}{200}=e^{kt}

y=200e^{kt}

Differentiate w.r.t

y'=200ke^{kt}

Substitute the given condition then, we get

100=200ke^{0}=200 \;because \;e^0=1

k=\frac{100}{200}=\frac{1}{2}

y=200e^{\frac{t}{2}}

Substitute t=2

Then, we get y=200e^{\frac{2}{2}}=200e

y=200(2.718)=543.6=543.6

e=2.718

Hence, the number of bacteria after 2 hours=543.6

4 0
3 years ago
Y = 5+5(x-8)<br> Can someone please solve this?
vekshin1

y = 5+5(x-8)

y = 5 + 5x - 40

y = 5x - 35

7 0
3 years ago
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